• Re: because =?UTF-8?Q?g=3F=28g=3F=C2=B9=28x=29=29=20=3D=20g=28y=29=20=5

    From WM@21:1/5 to All on Sat Apr 20 18:35:57 2024
    Le 20/04/2024 à 19:46, FromTheRafters a écrit :
    WM used his keyboard to write :

    Then that one directly before ω is not multiplied. Or it is not existing. But
    what exists directly before ω?

    All of the previous (finite) ordinals.

    Multiplying by 2 changes the multiplied ordinal.

    Regards, WM

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  • From WM@21:1/5 to All on Mon May 13 20:21:12 2024
    Le 10/05/2024 à 17:00, FromTheRafters a écrit :
    WM explained :

    Yes. But every n ∈ ℕ_def has ℵ₀ successors which never vanish by
    counting.
    They can be removed only collectively such that nothing of ℕ remains.

    Wrong,

    Try to remove all natural numbers individually from ℕ. Fail.

    Regards, WM

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  • From WM@21:1/5 to All on Tue May 14 11:10:27 2024
    Le 14/05/2024 à 00:47, FromTheRafters a écrit :
    WM expressed precisely :
    Le 10/05/2024 à 17:00, FromTheRafters a écrit :
    WM explained :

    Yes. But every n ∈ ℕ_def has ℵ₀ successors which never vanish by >>>> counting.
    They can be removed only collectively such that nothing of ℕ remains. >>>
    Wrong,

    Try to remove all natural numbers individually from ℕ. Fail.

    Because you cannot remove them -- *SETS DO NOT CHANGE*.

    But the result of subtraction can be calculated. That is understood by removing.

    Regards, WM

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  • From WM@21:1/5 to All on Tue May 14 11:15:22 2024
    Le 14/05/2024 à 01:32, "Chris M. Thomasson" a écrit :
    On 5/13/2024 1:21 PM, WM wrote:
    Le 10/05/2024 à 17:00, FromTheRafters a écrit :
    WM explained :

    Yes. But every n ∈ ℕ_def has ℵ₀ successors which never vanish by >>>> counting. They can be removed only collectively such that nothing of
    ℕ remains.

    Wrong,

    Try to remove all natural numbers individually from ℕ. Fail.

    Huh? ℕ is infinite in and of itself.

    Nevertheless all natural numbers can be removed collectively. But not individually. That shows a difference, resolved by numbers which can only
    be treated collectively: dark numbers.

    Regards, WM

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  • From WM@21:1/5 to All on Wed May 15 13:13:56 2024
    Le 14/05/2024 à 16:15, FromTheRafters a écrit :
    WM expressed precisely :
    Le 14/05/2024 à 00:47, FromTheRafters a écrit :
    WM expressed precisely :
    Le 10/05/2024 à 17:00, FromTheRafters a écrit :
    WM explained :

    Yes. But every n ∈ ℕ_def has ℵ₀ successors which never vanish by >>>>>> counting. They can be removed only collectively such that nothing of ℕ >>>>>> remains.

    Wrong,

    Try to remove all natural numbers individually from ℕ. Fail.

    Because you cannot remove them -- *SETS DO NOT CHANGE*.

    But the result of subtraction can be calculated. That is understood by
    removing.

    That is not quite the same as constructing a difference set.

    It is precisely the same. And if you disagree replace "removing" by "constructing a difference set".

    Regrds, WM

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  • From WM@21:1/5 to All on Wed May 15 13:18:46 2024
    Le 14/05/2024 à 16:26, Moebius a écrit :
    Am 13.05.2024 um 22:21 schrieb WM:

    Try to remove all natural numbers individually from ℕ.

    Wie stellst Du Dir das vor? Muss man sie in Mückenhausen einzeln von
    Hand removen? Das kann in der Praxis [->kein Supertask] lange dauern!

    You can remove what is removable individually.

    Ich hätte einen Alternativvorschlag: Man kann das mithilfe der "großen Differenz" (\\) so hinschreiben:

    IN \ {1} \ {2} \ {3} \ ... = IN \\ {{1}, {2}, {3}, ...}

    Ist das nicht "individuell" genug?

    Individually means you can name the individuals, at least the largest
    number of a removed finite initial segment.
    Collectively you can use the description of a species like positive
    integer.

    Regards, WM

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