Well there is no contraction in the number 2^(1/3) for exampleDidn't you learn yet that even the decimal RATIONAL field of numbers is also endless & unbounded
in the field of algebraic numbers. In the algebraic numbers,
numbers do not have to have the form p/q.
Am Donnerstag, 20. April 2017 17:04:07 UTC+2 schrieb bassam king karzeddin:
It seems you are a good student, very well acquainted in the subject, and talking in terms of sets
There is a good teacher in set theory here (WM), you certainly can learn a lot from him in this regard, for sure
But strangely, how is this related to our Title problem here, which is Angle Trisection? wonder!
Did you do it really? wonder!
So, good luck
BK
And strangely, this innocent recent post was not posted publicly from sci.math forum on 13/04/2017, wonder!them playing randomly any more,for sure
Despite being posted to my profile at sci.math forum! ****************************************
Dear Mathematicians in (04/09/2004),
I have posted in the geometry research the following
problem about angle trisection,but did not get a
clear opinion ,and, since, here is a larger group.
I will be glad to know if I wrote nonsense
mathematics or something useful.here is the problem.
An arbitrary angle and its exact trisection angle
fits exactly in the following symbolic triangle with
the following sides:
a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
Where : 2 >= b/a >= sqrt(2)
(a,b):are positive real numbers
Of course, I have a hand written proofs for this
fact.
Thanking you.
Bassam Karzeddin
Al Hussein Bin Talal University
JORDAN
********************************
And truly speaking, every existing angle is simply trisectible
But of course those majority of many fiction non existing angles are impossible to trisect, for sure
I had already explained those fiction angles based on fiction numbers in my recent posts with irrefutable proofs based on integer analysis and not simply on real or fake complex analysis, for sure
And really there wasn't any real puzzle except in understanding what was fiction non existing numbers
So, once the morons drop them they would certainly drop many puzzles to the hell
And the Greeks so unfortunately did not recognize this simple fact for sure, otherwise they would never ask such a silly Question, but truly (pi) had deceived them as being real number for sure,
Bassam King Karzeddin
13th, April, 2017
And still it is too funny that many childs in mathematics still claim true and exact constructions of (pi), and more funny that the moron types of big childes are also claiming exact construction of sqrt(pi) publically, wonder!
How many times it was proven that such number as (pi) never existed and would never exist except in the baboons minds for sure
They still round that small circle around a straight line and mark the point of start in full round as (pi) itself, ignoring the simplest fact that is only a scaled geometrical figure that never exists (which is actually a perfect circle)
Big Kids are really playing, and in fact and not to deny that they had played good enough in this regard, but when their play is becoming nonsense and more than fun, then, the real king is really angry, and would not keep silent any more, by letting
BK
On Saturday, April 15, 2017 at 8:49:11 AM UTC-7, bassam king karzeddin wrote:them playing randomly any more,for sure
And strangely, this innocent recent post was not posted publicly from sci.math forum on 13/04/2017, wonder!
Despite being posted to my profile at sci.math forum! ****************************************
Dear Mathematicians in (04/09/2004),
I have posted in the geometry research the following
problem about angle trisection,but did not get a
clear opinion ,and, since, here is a larger group.
I will be glad to know if I wrote nonsense
mathematics or something useful.here is the problem.
An arbitrary angle and its exact trisection angle
fits exactly in the following symbolic triangle with
the following sides:
a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
Where : 2 >= b/a >= sqrt(2)
(a,b):are positive real numbers
Of course, I have a hand written proofs for this
fact.
Thanking you.
Bassam Karzeddin
Al Hussein Bin Talal University
JORDAN
********************************
And truly speaking, every existing angle is simply trisectible
But of course those majority of many fiction non existing angles are impossible to trisect, for sure
I had already explained those fiction angles based on fiction numbers in my recent posts with irrefutable proofs based on integer analysis and not simply on real or fake complex analysis, for sure
And really there wasn't any real puzzle except in understanding what was fiction non existing numbers
So, once the morons drop them they would certainly drop many puzzles to the hell
And the Greeks so unfortunately did not recognize this simple fact for sure, otherwise they would never ask such a silly Question, but truly (pi) had deceived them as being real number for sure,
Bassam King Karzeddin
13th, April, 2017
And still it is too funny that many childs in mathematics still claim true and exact constructions of (pi), and more funny that the moron types of big childes are also claiming exact construction of sqrt(pi) publically, wonder!
How many times it was proven that such number as (pi) never existed and would never exist except in the baboons minds for sure
They still round that small circle around a straight line and mark the point of start in full round as (pi) itself, ignoring the simplest fact that is only a scaled geometrical figure that never exists (which is actually a perfect circle)
Big Kids are really playing, and in fact and not to deny that they had played good enough in this regard, but when their play is becoming nonsense and more than fun, then, the real king is really angry, and would not keep silent any more, by letting
BKOh, I get you. You want cube roots, and not any more for anybody else.
Might as well split cubes, dropping and flooring cubes, splitting cubes, here results cubes split, root, under additive or "under the root, the opposite of the differences", any expression maintains its order,
why not _quadrate_ the cubes regard phase, under quadrature,
here that the quadrature is in cubes.
The quadrature or square, has then the squaring, and, here usually
its pairs in square, then for cubes.
Then, is for that those, "rotate", under squares, "not like rotating internally,
but only flipping", of course what I mean here is you compute the space of cubes, and triples, making those are, is making, triples, area, then for adding
up the squares and pairs, into triples thus area.
See, what I mean here is putting up a squadature,above the root on just its even line, but all the analytic and periodic that exists about it, thusly, what
are "like line segments", add up to area terms, especially for the three-way case,
that the triples reduce to right angles thus half a whole quadrature, areas in and
areas out, Pythagorean triples, which can be enumerated, in area terms, and analyze
as the pythagorean triangles have integer sides so "all integer points fall out".
On Monday, October 2, 2023 at 7:40:38 PM UTC-7, Ross Finlayson wrote:letting them playing randomly any more,for sure
On Saturday, April 15, 2017 at 8:49:11 AM UTC-7, bassam king karzeddin wrote:
And strangely, this innocent recent post was not posted publicly from sci.math forum on 13/04/2017, wonder!
Despite being posted to my profile at sci.math forum! ****************************************
Dear Mathematicians in (04/09/2004),
I have posted in the geometry research the following
problem about angle trisection,but did not get a
clear opinion ,and, since, here is a larger group.
I will be glad to know if I wrote nonsense
mathematics or something useful.here is the problem.
An arbitrary angle and its exact trisection angle
fits exactly in the following symbolic triangle with
the following sides:
a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
Where : 2 >= b/a >= sqrt(2)
(a,b):are positive real numbers
Of course, I have a hand written proofs for this
fact.
Thanking you.
Bassam Karzeddin
Al Hussein Bin Talal University
JORDAN
********************************
And truly speaking, every existing angle is simply trisectible
But of course those majority of many fiction non existing angles are impossible to trisect, for sure
I had already explained those fiction angles based on fiction numbers in my recent posts with irrefutable proofs based on integer analysis and not simply on real or fake complex analysis, for sure
And really there wasn't any real puzzle except in understanding what was fiction non existing numbers
So, once the morons drop them they would certainly drop many puzzles to the hell
And the Greeks so unfortunately did not recognize this simple fact for sure, otherwise they would never ask such a silly Question, but truly (pi) had deceived them as being real number for sure,
Bassam King Karzeddin
13th, April, 2017
And still it is too funny that many childs in mathematics still claim true and exact constructions of (pi), and more funny that the moron types of big childes are also claiming exact construction of sqrt(pi) publically, wonder!
How many times it was proven that such number as (pi) never existed and would never exist except in the baboons minds for sure
They still round that small circle around a straight line and mark the point of start in full round as (pi) itself, ignoring the simplest fact that is only a scaled geometrical figure that never exists (which is actually a perfect circle)
Big Kids are really playing, and in fact and not to deny that they had played good enough in this regard, but when their play is becoming nonsense and more than fun, then, the real king is really angry, and would not keep silent any more, by
BKOh, I get you. You want cube roots, and not any more for anybody else.
Might as well split cubes, dropping and flooring cubes, splitting cubes, here results cubes split, root, under additive or "under the root, the opposite of the differences", any expression maintains its order,
why not _quadrate_ the cubes regard phase, under quadrature,
here that the quadrature is in cubes.
The quadrature or square, has then the squaring, and, here usually
its pairs in square, then for cubes.
Then, is for that those, "rotate", under squares, "not like rotating internally,
but only flipping", of course what I mean here is you compute the space of cubes, and triples, making those are, is making, triples, area, then for adding
up the squares and pairs, into triples thus area.
See, what I mean here is putting up a squadature,above the root on just itsWhich when are in thirds you can trisect them.
even line, but all the analytic and periodic that exists about it, thusly, what
are "like line segments", add up to area terms, especially for the three-way case,
that the triples reduce to right angles thus half a whole quadrature, areas in and
areas out, Pythagorean triples, which can be enumerated, in area terms, and analyze
as the pythagorean triangles have integer sides so "all integer points fall out".
On Tuesday, October 3, 2023 at 5:42:36 AM UTC+3, Ross Finlayson wrote:letting them playing randomly any more,for sure
On Monday, October 2, 2023 at 7:40:38 PM UTC-7, Ross Finlayson wrote:
On Saturday, April 15, 2017 at 8:49:11 AM UTC-7, bassam king karzeddin wrote:
And strangely, this innocent recent post was not posted publicly from sci.math forum on 13/04/2017, wonder!
Despite being posted to my profile at sci.math forum! ****************************************
Dear Mathematicians in (04/09/2004),
I have posted in the geometry research the following
problem about angle trisection,but did not get a
clear opinion ,and, since, here is a larger group.
I will be glad to know if I wrote nonsense
mathematics or something useful.here is the problem.
An arbitrary angle and its exact trisection angle
fits exactly in the following symbolic triangle with
the following sides:
a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
Where : 2 >= b/a >= sqrt(2)
(a,b):are positive real numbers
Of course, I have a hand written proofs for this
fact.
Thanking you.
Bassam Karzeddin
Al Hussein Bin Talal University
JORDAN
********************************
And truly speaking, every existing angle is simply trisectible
But of course those majority of many fiction non existing angles are impossible to trisect, for sure
I had already explained those fiction angles based on fiction numbers in my recent posts with irrefutable proofs based on integer analysis and not simply on real or fake complex analysis, for sure
And really there wasn't any real puzzle except in understanding what was fiction non existing numbers
So, once the morons drop them they would certainly drop many puzzles to the hell
And the Greeks so unfortunately did not recognize this simple fact for sure, otherwise they would never ask such a silly Question, but truly (pi) had deceived them as being real number for sure,
Bassam King Karzeddin
13th, April, 2017
And still it is too funny that many childs in mathematics still claim true and exact constructions of (pi), and more funny that the moron types of big childes are also claiming exact construction of sqrt(pi) publically, wonder!
How many times it was proven that such number as (pi) never existed and would never exist except in the baboons minds for sure
They still round that small circle around a straight line and mark the point of start in full round as (pi) itself, ignoring the simplest fact that is only a scaled geometrical figure that never exists (which is actually a perfect circle)
Big Kids are really playing, and in fact and not to deny that they had played good enough in this regard, but when their play is becoming nonsense and more than fun, then, the real king is really angry, and would not keep silent any more, by
BKOh, I get you. You want cube roots, and not any more for anybody else.
Might as well split cubes, dropping and flooring cubes, splitting cubes, here results cubes split, root, under additive or "under the root, the opposite of the differences", any expression maintains its order,
why not _quadrate_ the cubes regard phase, under quadrature,
here that the quadrature is in cubes.
The quadrature or square, has then the squaring, and, here usually
its pairs in square, then for cubes.
Then, is for that those, "rotate", under squares, "not like rotating internally,
but only flipping", of course what I mean here is you compute the space of
cubes, and triples, making those are, is making, triples, area, then for adding
up the squares and pairs, into triples thus area.
The integer degree angles that are divisible by 3, are existing anglesSee, what I mean here is putting up a squadature,above the root on just itsWhich when are in thirds you can trisect them.
even line, but all the analytic and periodic that exists about it, thusly, what
are "like line segments", add up to area terms, especially for the three-way case,
that the triples reduce to right angles thus half a whole quadrature, areas in and
areas out, Pythagorean triples, which can be enumerated, in area terms, and analyze
as the pythagorean triangles have integer sides so "all integer points fall out".
The non-existing angles in degrees are :
(1, 2, 4, 5, 7, 8, 10, 11, ...88, 89)
I.e , two-thirds of integer degrees angles don't exist
Ie, it is absolutely the seventh impossible to have a triangle with exactly known sides having at least one of its angles as any of the above mentioned angles
BKK
And strangely, this innocent recent post was not posted publicly from sci.math forum on 13/04/2017, wonder!
Despite being posted to my profile at sci.math forum! ****************************************
Dear Mathematicians in (04/09/2004),
I have posted in the geometry research the following
problem about angle trisection,but did not get a
clear opinion ,and, since, here is a larger group.
I will be glad to know if I wrote nonsense
mathematics or something useful.here is the problem.
An arbitrary angle and its exact trisection angle
fits exactly in the following symbolic triangle with
the following sides:
a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
Where : 2 >= b/a >= sqrt(2)
(a,b):are positive real numbers
Of course, I have a hand written proofs for this
fact.
Thanking you.
Bassam Karzeddin
Al Hussein Bin Talal University
JORDAN
********************************
And truly speaking, every existing angle is simply trisectible
But of course those majority of mCany fiction non existing angles are impossible to trisect, for surethem playing randomly any more,for sure
I had already explained those fiction angles based on fiction numbers in my recent posts with irrefutable proofs based on integer analysis and not simply on real or fake complex analysis, for sure
And really there wasn't any real puzzle except in understanding what was fiction non existing numbers
So, once the morons drop them they would certainly drop many puzzles to the hell
And the Greeks so unfortunately did not recognize this simple fact for sure, otherwise they would never ask such a silly Question, but truly (pi) had deceived them as being real number for sure,
Bassam King Karzeddin
13th, April, 2017
And still it is too funny that many childs in mathematics still claim true and exact constructions of (pi), and more funny that the moron types of big childes are also claiming exact construction of sqrt(pi) publically, wonder!
How many times it was proven that such number as (pi) never existed and would never exist except in the baboons minds for sure
They still round that small circle around a straight line and mark the point of start in full round as (pi) itself, ignoring the simplest fact that is only a scaled geometrical figure that never exists (which is actually a perfect circle)
Big Kids are really playing, and in fact and not to deny that they had played good enough in this regard, but when their play is becoming nonsense and more than fun, then, the real king is really angry, and would not keep silent any more, by letting
BK
And strangely, this innocent recent post was not posted publicly from sci.math forum on 13/04/2017, wonder!them playing randomly any more,for sure
Despite being posted to my profile at sci.math forum! ****************************************
Dear Mathematicians in (04/09/2004),
I have posted in the geometry research the following
problem about angle trisection,but did not get a
clear opinion ,and, since, here is a larger group.
I will be glad to know if I wrote nonsense
mathematics or something useful.here is the problem.
An arbitrary angle and its exact trisection angle
fits exactly in the following symbolic triangle with
the following sides:
a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
Where : 2 >= b/a >= sqrt(2)
(a,b):are positive real numbers
Of course, I have a hand written proofs for this
fact.
Thanking you.
Bassam Karzeddin
Al Hussein Bin Talal University
JORDAN
********************************
And truly speaking, every existing angle is simply trisectible
But of course those majority of many fiction non existing angles are impossible to trisect, for sure
I had already explained those fiction angles based on fiction numbers in my recent posts with irrefutable proofs based on integer analysis and not simply on real or fake complex analysis, for sure
And really there wasn't any real puzzle except in understanding what was fiction non existing numbers
So, once the morons drop them they would certainly drop many puzzles to the hell
And the Greeks so unfortunately did not recognize this simple fact for sure, otherwise they would never ask such a silly Question, but truly (pi) had deceived them as being real number for sure,
Bassam King Karzeddin
13th, April, 2017
And still it is too funny that many childs in mathematics still claim true and exact constructions of (pi), and more funny that the moron types of big childes are also claiming exact construction of sqrt(pi) publically, wonder!
How many times it was proven that such number as (pi) never existed and would never exist except in the baboons minds for sure
They still round that small circle around a straight line and mark the point of start in full round as (pi) itself, ignoring the simplest fact that is only a scaled geometrical figure that never exists (which is actually a perfect circle)
Big Kids are really playing, and in fact and not to deny that they had played good enough in this regard, but when their play is becoming nonsense and more than fun, then, the real king is really angry, and would not keep silent any more, by letting
BK
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