Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

--

"If God wanted us to believe in him, he'd exist."

(Linda Smith on "10 Funniest Londoners", TimeOut, 23rd June, 2005.)

--- SoupGate-Win32 v1.05
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On 11/30/22 12:59, Kenny McCormack wrote:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

Instead of the $ that a regex would use to match the end of a string,
use the shell wildcard * to match anything. Then use & in the
replacement text to insert whatever matched that pattern:

$ someCommand "${@/*/&\/*.c}"

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Ben Bacarisse <ben.usenet@bsb.me.uk> writes:

gazelle@shell.xmission.com (Kenny McCormack) writes:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

echo "${@/*/&\/*.c}"

But there is also new syntax I've not seem before:

echo "${@/%/\/*.c}"

(/# and /% match at the beginning and the end so here we match nothing
at the end)

--
Ben.

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gazelle@shell.xmission.com (Kenny McCormack) writes:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

echo "${@/*/&\/*.c}"

--
Ben.

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On 2022-11-30, Kenny McCormack <gazelle@shell.xmission.com> wrote:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

If the pattern starts with '%', it is matched at the end. That
also works with an empty pattern:

$ someCommand "${@/%//*.c}"

I seem to remember that there is a way to do this, but I can't recall it
ATM.

I had no idea this was possible, until I checked the man page.

--
Christian "naddy" Weisgerber naddy@mips.inka.de

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On 30.11.2022 18:59, Kenny McCormack wrote:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

You've already got an answer using ${var/%...} which can (obviously in
bash and zsh, but not in ksh) be simply written as "${@/%/.c}"

$ set -- foo bar bletch
$ echo "${@/%/.c}"

(the more complex syntax in the other post produces "foo\/*.c bar\/*.c bletch\/*.c" in my environment which is not what I'd expect)

If you want to avoid using/overwriting the positional parameters you can
also use that pattern with array variables

$ arr=( foo bar bletch )
$ printf "'%s'\n" "${arr[@]/%/.c}"

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

Unless having a need for the arguments to be stored as $@, and the 'set'
is just a part of the test sample you can use brace expansion (at least
for constant file lists) like

$ echo {foo,bar,bletch}.c


Janis

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On 30.11.2022 23:59, Janis Papanagnou wrote:

$ arr=( foo bar bletch )
$ printf "'%s'\n" "${arr[@]/%/.c}"

$ arr=( foo bar bletch )
$ echo "${arr[@]/%/.c}"

Forgot to simplify that variant for the post (for clarity).

Janis

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In article <87h6ygb3j3.fsf@bsb.me.uk>,
Ben Bacarisse <ben.usenet@bsb.me.uk> wrote:

Ben Bacarisse <ben.usenet@bsb.me.uk> writes:

gazelle@shell.xmission.com (Kenny McCormack) writes:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it. >>>
Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

I seem to remember that there is a way to do this, but I can't recall it >>> ATM. Any ideas?

echo "${@/*/&\/*.c}"

But there is also new syntax I've not seem before:

echo "${@/%/\/*.c}"

(/# and /% match at the beginning and the end so here we match nothing
at the end)

Thanks. These both looks like useful suggestions. I haven't tested them
yet, but it looks right.

--
A 70 year old man who watches 6 hours of TV a day, plays a lot of golf
and seems to always be in Florida is a retiree, not a president.

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you are looking for shell brace expansion:

https://www.gnu.org/software/bash/manual/html_node/Brace-Expansion.html

echo {foo,bar,bletch}.c

pre, and post, nested, ... all work. good luck

On Thursday, December 1, 2022 at 3:58:21 AM UTC-5, Kenny McCormack wrote:

In article <87h6ygb...@bsb.me.uk>,
Ben Bacarisse <ben.u...@bsb.me.uk> wrote:

Ben Bacarisse <ben.u...@bsb.me.uk> writes:

gaz...@shell.xmission.com (Kenny McCormack) writes:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it. >>>
Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each. >>
I seem to remember that there is a way to do this, but I can't recall it >>> ATM. Any ideas?

echo "${@/*/&\/*.c}"

But there is also new syntax I've not seem before:

echo "${@/%/\/*.c}"

(/# and /% match at the beginning and the end so here we match nothing
at the end)

Thanks. These both looks like useful suggestions. I haven't tested them
yet, but it looks right.

--
A 70 year old man who watches 6 hours of TV a day, plays a lot of golf
and seems to always be in Florida is a retiree, not a president.

--- SoupGate-Win32 v1.05
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In article <556afb46-f290-42d4-b159-d4ccff867de9n@googlegroups.com>,
applemcg <marty.mcgowan@gmail.com> wrote:

you are looking for shell brace expansion:

No, I'm not.

You might want to re-read the original post.

--
It's all Al Gore's fault...

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On Thursday, December 1, 2022 at 9:43:19 AM UTC-5, Kenny McCormack wrote:

In article <556afb46-f290-42d4...@googlegroups.com>,
applemcg <marty....@gmail.com> wrote:

you are looking for shell brace expansion:

No, I'm not.

You might want to re-read the original post.

--
It's all Al Gore's fault...

Why not this then, I missed the slash:

lib.$ set {foo,bar,zot}/*.c
lib.$ ea
3 foo/*.c bar/*.c zot/*.c
lib.$

p.s. i somehow got hooked on "zot" as rounding out the trio.

might i ask why shell brace expansion isn't a solution. i was moved by the OP:

"I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas? "

this is a suitable idea.

--- SoupGate-Win32 v1.05
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In article <7a1a6b31-4202-4937-aad3-7da4dfb20e03n@googlegroups.com>,
applemcg <marty.mcgowan@gmail.com> wrote:

On Thursday, December 1, 2022 at 9:43:19 AM UTC-5, Kenny McCormack wrote:

In article <556afb46-f290-42d4...@googlegroups.com>,
applemcg <marty....@gmail.com> wrote:

you are looking for shell brace expansion:

No, I'm not.

You might want to re-read the original post.

...

Why not this then, I missed the slash:

lib.$ set {foo,bar,zot}/*.c
lib.$ ea
3 foo/*.c bar/*.c zot/*.c
lib.$

p.s. i somehow got hooked on "zot" as rounding out the trio.

might i ask why shell brace expansion isn't a solution.

It is close, but doesn't quite work.

The problem is that, in real life, the contents of $@ comes from the
command line invocation of the script, not from "set --".

So, you need a way to get from "$@" to {contents,of,that,variable}/"*.c".
I've grappled with this problem before in other contexts - getting from a
shell variable to brace expansion. It can be done, but it is messy.

Also, although not made 100% clear in the OP, I need it to end with *.c,
not with an expansion of all the C source files in the directory. Hence,
you need to quote it as above.

--
The randomly chosen signature file that would have appeared here is more than 4 lines long. As such, it violates one or more Usenet RFCs. In order to remain in compliance with said RFCs, the actual sig can be found at the following URL:
http://user.xmission.com/~gazelle/Sigs/RoyDeLoon

--- SoupGate-Win32 v1.05
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On 30/11/2022 19:59, Janis Papanagnou wrote:

On 30.11.2022 18:59, Kenny McCormack wrote:

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

You've already got an answer using ${var/%...} which can (obviously in
bash and zsh, but not in ksh) be simply written as "${@/%/.c}"

$ set -- foo bar bletch
$ echo "${@/%/.c}"

(the more complex syntax in the other post produces "foo\/*.c bar\/*.c bletch\/*.c" in my environment which is not what I'd expect)

If you want to avoid using/overwriting the positional parameters you can
also use that pattern with array variables

$ arr=( foo bar bletch )
$ printf "'%s'\n" "${arr[@]/%/.c}"

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

Unless having a need for the arguments to be stored as $@, and the 'set'
is just a part of the test sample you can use brace expansion (at least
for constant file lists) like

$ echo {foo,bar,bletch}.c

Janis

So what does Janis mean? Is that a nickname?

Well, I wonder, Janis Joplin. Like a bi singer.+

That would be too great to have a woman looking at our code

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On 30/11/2022 20:03, Janis Papanagnou wrote:

Janis Papanagnou

just a nickname, i have seen on google search, they may deem Janis as woman perhaps not

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On 18/01/2023 00:33, castAway wrote:

On 30/11/2022 20:03, Janis Papanagnou wrote:

Janis Papanagnou

just a nickname, i have seen on google search, they may deem Janis as woman perhaps not

as far as i know, he is is a boy

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On 18.01.2023 04:31, castAway wrote:

On 30/11/2022 19:59, Janis Papanagnou wrote:

Janis

So what does Janis mean? Is that a nickname?

It's a common forename you find in western Christian cultures that is
very common in many countries in their own country specific forms.
Mine stems from the Greek culture where the non-abbreviated spelling
is Ioannis. In anglo-american cultures it's usually written as Yanis;
see also the prominent Yanis Varoufakis (university professor in the
USA, IIRC, and temporarily part of the Greek government during the
financial crisis a decade ago).

So, no, it's (in this case) not a nickname. I prefer posting by real
name, while otherwise trying to keep my privacy intact - if (e.g.)
you're using google to find pictures of me you get only pictures of
other persons (even female ones) despite, I dare to say, that Janis
Papanagnou is a quite unique name combination even world wide.

Well, I wonder, Janis Joplin. Like a bi singer.+

I always wondered whether that was a phonetic transcription of the
name Janice or a normal female name in the USA. Besides Janis Joplin
I've never seem that name given to a woman (but who am I to know).

That would be too great to have a woman looking at our code

I'm sorry to have to disappoint you here. :-)

Myself I prefer to not distinguish personalities by gender; respect
everyone as he or she deserves it.

(OTOH it's indeed strange that there's so few (or even no) female
posters around here.)

Janis

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On Wed, 18 Jan 2023 06:34:53 +0100
Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

On 18.01.2023 04:31, castAway wrote:

On 30/11/2022 19:59, Janis Papanagnou wrote:

Janis

So what does Janis mean? Is that a nickname?

It's a common forename you find in western Christian cultures that is
very common in many countries in their own country specific forms.

Like John in English or Johannes in German.

Mine stems from the Greek culture where the non-abbreviated spelling
is Ioannis. In anglo-american cultures it's usually written as Yanis;

Or Yianis or Yiannis. In German "J" is pronounced differently than in
English so for a German speaking person the natural pronunciation of
"Janis" is Yianis. I think in German "judo" is pronounced yioudo.

see also the prominent Yanis Varoufakis (university professor in the
USA, IIRC, and temporarily part of the Greek government during the
financial crisis a decade ago).

So, no, it's (in this case) not a nickname. I prefer posting by real
name, while otherwise trying to keep my privacy intact - if (e.g.)

[...]

(OTOH it's indeed strange that there's so few (or even no) female
posters around here.)

This is the case on all comp* groups I frequent. On the other hand , rec.arts.sf.written has quite a few.

--
"Ensign Crusher is in Sickbay receiving fellatio from his mother."
"Oh no, not again," groans the Captain.
"He is not a true warrior!" exclaims Worf.
http://groups.google.co.uk/group/alt.wesley.crusher.die.die.die/msg/8cc93193b362302b

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On 18.01.2023 12:58, Spiros Bousbouras wrote:

On Wed, 18 Jan 2023 06:34:53 +0100
Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

On 18.01.2023 04:31, castAway wrote:

On 30/11/2022 19:59, Janis Papanagnou wrote:

Janis

So what does Janis mean? Is that a nickname?

It's a common forename you find in western Christian cultures that is
very common in many countries in their own country specific forms.

Like John in English or Johannes in German.

Exactly. And there's also abbreviated derived name forms like "Hans"
(in German). Also in other [Christian] countries it's typically a
very very common name; e.g. Jean in France, Giovanni in Italy, Juan
in Spanish, or Ivan in Russia, just to name a few prominent ones.
The Wikipedia has a nice thorough list of yet more language forms: https://en.wikipedia.org/wiki/Johannes

Janis

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On Wed, 18 Jan 2023 06:34:53 +0100, Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

On 18.01.2023 04:31, castAway wrote:

..
Well, I wonder, Janis Joplin. Like a bi singer.+

I always wondered whether that was a phonetic transcription of the
name Janice or a normal female name in the USA. Besides Janis Joplin
I've never seem that name given to a woman (but who am I to know).

You might know the song "Run too fast fly too high" from Janis Ian. :)

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On Wed, 18 Jan 2023 06:34:53 +0100
Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

(OTOH it's indeed strange that there's so few (or even no) female
posters around here.)

If it helps, I read this group sometimes. But I've never posted here...
before now.

We do exist!

- Sophie.

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On 19.01.2023 13:20, Sophie Hamilton wrote:

On Wed, 18 Jan 2023 06:34:53 +0100
Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

(OTOH it's indeed strange that there's so few (or even no) female
posters around here.)

If it helps, I read this group sometimes. But I've never posted here... before now.

We do exist!

Glad to hear! :-)

Janis

- Sophie.

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Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

On 18.01.2023 04:31, castAway wrote:

On 30/11/2022 19:59, Janis Papanagnou wrote:

Janis

So what does Janis mean? Is that a nickname?

It's a common forename you find in western Christian cultures that is
very common in many countries in their own country specific forms.
Mine stems from the Greek culture where the non-abbreviated spelling
is Ioannis. In anglo-american cultures it's usually written as Yanis;
see also the prominent Yanis Varoufakis (university professor in the
USA, IIRC, and temporarily part of the Greek government during the
financial crisis a decade ago).

So, no, it's (in this case) not a nickname. I prefer posting by real
name, while otherwise trying to keep my privacy intact - if (e.g.)
you're using google to find pictures of me you get only pictures of
other persons (even female ones) despite, I dare to say, that Janis Papanagnou is a quite unique name combination even world wide.

Well, I wonder, Janis Joplin. Like a bi singer.+

I always wondered whether that was a phonetic transcription of the
name Janice or a normal female name in the USA. Besides Janis Joplin
I've never seem that name given to a woman (but who am I to know).

That would be too great to have a woman looking at our code

I'm sorry to have to disappoint you here. :-)

Myself I prefer to not distinguish personalities by gender; respect
everyone as he or she deserves it.

(OTOH it's indeed strange that there's so few (or even no) female
posters around here.)

Janis

I found this:

What does Janis mean?

Janis Pronunciation of Janis ? as a name for girls is a Hebrew name,
and Janis means "God is gracious". Janis is an alternate spelling
of Jane (Hebrew): originally a feminine respelling of John. Janis
is also a variation of Janice (Hebrew).

http://www.thinkbabynames.com/meaning/0/Janis

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On 2023-01-22, Jerry Peters <jerry@example.invalid> wrote:

Janis Papanagnou <janis_papanagnou+ng@hotmail.com> wrote:

On 18.01.2023 04:31, castAway wrote:

On 30/11/2022 19:59, Janis Papanagnou wrote:

Janis

So what does Janis mean? Is that a nickname?

It's a common forename you find in western Christian cultures that is
very common in many countries in their own country specific forms.
Mine stems from the Greek culture where the non-abbreviated spelling
is Ioannis. In anglo-american cultures it's usually written as Yanis;
see also the prominent Yanis Varoufakis (university professor in the
USA, IIRC, and temporarily part of the Greek government during the
financial crisis a decade ago).

So, no, it's (in this case) not a nickname. I prefer posting by real
name, while otherwise trying to keep my privacy intact - if (e.g.)
you're using google to find pictures of me you get only pictures of
other persons (even female ones) despite, I dare to say, that Janis
Papanagnou is a quite unique name combination even world wide.

Well, I wonder, Janis Joplin. Like a bi singer.+

I always wondered whether that was a phonetic transcription of the
name Janice or a normal female name in the USA. Besides Janis Joplin
I've never seem that name given to a woman (but who am I to know).

That would be too great to have a woman looking at our code

I'm sorry to have to disappoint you here. :-)

Myself I prefer to not distinguish personalities by gender; respect
everyone as he or she deserves it.

(OTOH it's indeed strange that there's so few (or even no) female
posters around here.)

Janis

I found this:

What does Janis mean?

Janis Pronunciation of Janis ? as a name for girls is a Hebrew name,
and Janis means "God is gracious". Janis is an alternate spelling
of Jane (Hebrew): originally a feminine respelling of John. Janis
is also a variation of Janice (Hebrew).

http://www.thinkbabynames.com/meaning/0/Janis

And in Latvian Janis (there's a squiggle over the N, I think) is pronounced YAWN-iss and is the Latvian equivalent of "John".

pH in Aptos whose mom was latvian

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On 2023-01-23, pH <wNOSPAMp@gmail.org> wrote:

http://www.thinkbabynames.com/meaning/0/Janis

And in Latvian Janis (there's a squiggle over the N, I think) is pronounced YAWN-iss and is the Latvian equivalent of "John".

There is no "squiggle over the N" in Latvian orthography.

Go to Wikipedia, pick an article on one of the Biblical Johns, look
at the corresponding article in Latvian (Latviešu), there it is.

The diacritic in this case is a bar (macron) over the a: Jānis.

--
Christian "naddy" Weisgerber naddy@mips.inka.de

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On Mon, 23 Jan 2023 09:55:38 -0000 (UTC), Christian Weisgerber <naddy@mips.inka.de> wrote:

The diacritic in this case is a bar (macron) over the a: J?nis.

Which means it is a long 'a'. https://translate.google.com/?sl=lv&tl=en&text=J%C4%81nis&op=translate
--
no sig

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On 30/11/2022 at 18:59, Kenny McCormack wrote :

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

Hi,

$ set -- cp dd
$ echo ${@/%/\/*.c}
cp/cp.c cp/utils.c dd/args.c dd/conv.c dd/conv_tab.c dd/dd.c dd/gen.c
dd/misc.c dd/position.c
$ echo "${@/%/\/*.c}"
cp/*.c dd/*.c

/% means replace from the end
/# from the beginning

Regards,

Cyrille Lefevre.
--
mailto:Cyrille.Lefevre-news%nospam@laposte.net.invalid
remove "%nospam" and ".invalid" to answer me.

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In article <653b39b4$0$7462$426a34cc@news.free.fr>,
Cyrille Lefevre <Cyrille.Lefevre-news%nospam@laposte.net.invalid> wrote:

On 30/11/2022 at 18:59, Kenny McCormack wrote :

Note: not looking for workarounds, got plenty of my own.
In particular, if you have to code a loop, that takes the fun out of it.

Anyway, suppose I do:

$ set -- foo bar bletch

I want to pass these args to a subprogram with "/*.c" appended to each.

So, I'd like for:

$ someCommand "${@/$/\/*.c}"

to work, but it does not. This is b/c the above bash syntax doesn't deal
in reg exps; it is some other kind of pattern matcher.

I seem to remember that there is a way to do this, but I can't recall it
ATM. Any ideas?

Hi,

$ set -- cp dd
$ echo ${@/%/\/*.c}
cp/cp.c cp/utils.c dd/args.c dd/conv.c dd/conv_tab.c dd/dd.c dd/gen.c >dd/misc.c dd/position.c
$ echo "${@/%/\/*.c}"
cp/*.c dd/*.c

/% means replace from the end
/# from the beginning

Yes! Thank you! This is Usenet working as it was intended. A rarity
these days!

And, indeed, I found this in "man bash":

${parameter/pattern/string}
Pattern substitution. The pattern is expanded to produce a pat-
tern just as in pathname expansion. Parameter is expanded and
the longest match of pattern against its value is replaced with
string. If pattern begins with /, all matches of pattern are
replaced with string. Normally only the first match is
replaced. If pattern begins with #, it must match at the begin-
ning of the expanded value of parameter. If pattern begins with
%, it must match at the end of the expanded value of parameter.
If string is null, matches of pattern are deleted and the / fol-
lowing pattern may be omitted. If parameter is @ or *, the sub-
stitution operation is applied to each positional parameter in
turn, and the expansion is the resultant list. If parameter is
an array variable subscripted with @ or *, the substitution
operation is applied to each member of the array in turn, and
the expansion is the resultant list.

The bit about % and # is there in the text. I just never noticed it before.

--
Life's big questions are big in the sense that they are momentous. However, contrary to
appearances, they are not big in the sense of being unanswerable. It is only that the answers
are generally unpalatable. There is no great mystery, but there is plenty of horror.
(https://en.wikiquote.org/wiki/David_Benatar)

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