Kinetic Energy formula check - a series of short burn rockets, and seeIs this one of the reasons why France split between Engineering Schools
how the velocity adds up.
Is it v or v^2?
Is this formula E=0.5mv^2 correct, or is it more like E= mv?
Also can calculate the kinetic energy before and after each stage -
check velocity from the experimental apparatus.
Ideally use an airtrack - no rotational inertia to be concerned with.
Needs good design so each rocket burn adds the same energy.
Remember this correction is for basic, military and professional
education - nothing to do with university.
This is bread and butter basic physics.
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Kinetic Energy formula check - a series of short burn rockets, and see
how the velocity adds up.
Is it v or v^2?
Is this formula E=0.5mv^2 correct, or is it more like E= mv?
Is it v or v^2?
Is this formula E=0.5mv^2 correct, or is it more like E= mv?
Am 08.01.2023 um 10:36 schrieb Dave:
Is it v or v^2?
Is this formula E=0.5mv^2 correct, or is it more like E= mv?
That should depend on the used units for E, m and v.
As unit systems have different degrees of internal consistency, you
should certainly be able to find an example for both factors.
I usually use SI units only and would get 0.5 as factor, but have not verified the exponent 2 myself.
In general I would prefer the quantity momentum over energy, because
v is frame dependent, hence also kinetic energy.
Then I would like to compare conservation of momentum and
conservation of energy, but suggest choosing conservation of momentum
over conservation of energy.
TH
Momentum is useful in particular situations, for example solving
problems involving snooker balls. Anything involving resonance is best understood in terms of energy, as resonance is the repeated conversion
of one type of energy to another, and back again.
Am 09.01.2023 um 15:13 schrieb Joe:
...
Momentum is useful in particular situations, for example solving
problems involving snooker balls. Anything involving resonance is best
understood in terms of energy, as resonance is the repeated conversion
of one type of energy to another, and back again.
My problem with momentum and energy is, that momentum is known to be a conserved quantity and energy assumed to be.
But momentum is m*v, while kinetic energy is 1/2 *m *vē.
How could both quantities possibly be both conserved for the same
object, with same mass m and same velocity v, if one curve of that
quantity over v is linear with v and one quadratic ????
If v gets smaller a little, than both curves cannot possibly coincide
with their respective conservation curve, hence one quantity is not conserved, if v is altered. But we can easily alter v, because v is
frame dependent. And choosing a different coordinate system should not
alter the state of an object, hence neither energy nor momentum.
Kinetic Energy formula check - a series of short burn rockets, and see
how the velocity adds up.
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