On Tue, 23 Jul 2024 15:44:59 +0000, Richard Hachel wrote:
Here is a sentence from Dr. Hachel with which physicists do not agree at
all.
It's a shame.
When an individual disagrees with another individual on a scientific
theory or fact, it would be normal to ask the other party to sit down
and
explain why they are behaving in an outlandish-looking manner. , and why
it "thinks differently".
This would be a proof of logic and human coherence.
"If two mobiles, one in simple Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
This is false in general.
<http://news2.nemoweb.net/jntp?i6e6RaE0RxCNtGlAaSfIYZlkB2s@jntp/Data.Media:1>
The problem for physicists is that, on the other hand, they do not
understand the drawing on the right, we always have Tr, x/c, and To.
This is basic calculus, the length of a curve. Why is this so confusing
to you?
The length of the blue line is the length of the blue line.
Sorry but
this
is simply what it is. It's not equal to any of the straight chord lines lengths.
Jan
On Tue, 23 Jul 2024 15:44:59 +0000, Richard Hachel wrote:
Here is a sentence from Dr. Hachel with which physicists do not agree at
all.
It's a shame.
When an individual disagrees with another individual on a scientific
theory or fact, it would be normal to ask the other party to sit down
and
explain why they are behaving in an outlandish-looking manner. , and why
it "thinks differently".
This would be a proof of logic and human coherence.
"If two mobiles, one in simple Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
This is false in general.
Where does the physicists' error come from?
What error?
Here is a sentence from Dr. Hachel with which physicists do not agree at all. It's a shame.
When an individual disagrees with another individual on a scientific
theory or fact, it would be normal to ask the other party to sit down
and explain why they are behaving in an outlandish-looking manner. ,
and why it "thinks differently".
This would be a proof of logic and human coherence.
"If two mobiles, one in simple Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
Le 23/07/2024 à 23:57, film.art@gmail.com (JanPB) a écrit :
On Tue, 23 Jul 2024 15:44:59 +0000, Richard Hachel wrote:
"If two mobiles, one in simple Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
This is false in general.
I beg you to show a little politeness.
I know very well that this is generally false.
Den 24.07.2024 00:35, skrev Richard Hachel:
Le 23/07/2024 à 23:57, film.art@gmail.com (JanPB) a écrit :
On Tue, 23 Jul 2024 15:44:59 +0000, Richard Hachel wrote:
"If two mobiles, one in simple Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
This is false in general.
I beg you to show a little politeness.
I know very well that this is generally false.
.. but still claim it is true! :-D
then their proper times will be equal."
That sentence contains an undefined term "Galilean movement".
Therefore no agreement is possible.
Mikko
Le 24/07/2024 à 11:03, Mikko a écrit :
On 2024-07-23 15:44:59 +0000, Richard Hachel said:
"If two mobiles, one in simple Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
That sentence contains an undefined term "Galilean movement".
Therefore no agreement is possible.
Mikko
Vous avez raison.
Il est plus précis de dire :
"If two mobiles, one in simple uniform Galilean movement,
the other in uniformly accelerated movement with a start at rest,
cross an identical space, in identical observable times,
then their proper times will be equal."
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