I have posted several times, here or elsewhere, details on the equality
of proper tenses in certain cases.
I said, speaking of the two travelers from Tau Ceti (variant of the problem where the traveler was alone), that if the observable
(terrestrial) times of the two protagonists were the same (they leave together, cross the same space of 12 ly, and arrive at the same time,
then their own times would be equal.
One of the travelers is in uniform Galilean motion (Vo=0.9291c), the
other is in accelerated motion (a=1.052 ly/y²).
This seems to surprise relativistic physicists.
Who is lying? Who tells the truth?
R.H.
Den 17.10.2023 15:43, skrev Richard Hachel:
I have posted several times, here or elsewhere, details on the equality
of proper tenses in certain cases.
I said, speaking of the two travelers from Tau Ceti (variant of the
problem where the traveler was alone), that if the observable
(terrestrial) times of the two protagonists were the same (they leave
together, cross the same space of 12 ly, and arrive at the same time,
then their own times would be equal.
I suppose "their own time" means their proper time.
One of the travelers is in uniform Galilean motion (Vo=0.9291c), the
other is in accelerated motion (a=1.052 ly/y²).
c = 1 ly/y
d = 12 ly
Accelerated traveller:
a = 1.052 ly/y²
terrestrial time: t₁ = √((d/c)²+2d/a) = 12.9156 y
proper time: τ₁ = (c/a)⋅arsinh(at₁/c) = 3.1403 y
Inertial traveller:
v = 0.9291 ly/y
γ = √(1−v²/c²) = 2.703955
terrestrial time: t₂ = d/v = 12.9157 y
proper time: τ₂ = t₂/γ = 4.7766 y
This seems to surprise relativistic physicists.
The proper times are not equal.
No point in going on.
Who is lying? Who tells the truth?
R.H.
You are not lying because you don't know better.
But you are wrong.
Le 17/10/2023 à 20:52, "Paul B. Andersen" a écrit :
Den 17.10.2023 15:43, skrev Richard Hachel:
I have posted several times, here or elsewhere, details on the
equality of proper tenses in certain cases.
I said, speaking of the two travelers from Tau Ceti (variant of the
problem where the traveler was alone), that if the observable
(terrestrial) times of the two protagonists were the same (they leave
together, cross the same space of 12 ly, and arrive at the same time,
then their own times would be equal.
I suppose "their own time" means their proper time.
One of the travelers is in uniform Galilean motion (Vo=0.9291c),
the other is in accelerated motion (a=1.052 ly/y²).
c = 1 ly/y
Yes.
d = 12 ly
Absolutely.
Accelerated traveller:
a = 1.052 ly/y²
Sure.
terrestrial time: t₁ = √((d/c)²+2d/a) = 12.9156 y
It's that I said.
proper time: τ₁ = (c/a)⋅arsinh(at₁/c) = 3.1403 y
This formula is not correct.
This is the one that is taught.
But it is not correct.This formula is not correct.
This is the one that is taught.
But it is not correct.
Inertial traveller:
v = 0.9291 ly/y
Yes.
γ = √(1−v²/c²) = 2.703955
terrestrial time: t₂ = d/v = 12.9157 y
Yes.
proper time: τ₂ = t₂/γ = 4.7766 y
Yes.
This seems to surprise relativistic physicists.
The proper times are not equal.
The proper times, in this particular case, must be equal.
Den 17.10.2023 21:09, skrev Richard Hachel:
But it is not correct.
It is what SR predicts.
The proper times are not equal.
The proper times, in this particular case, must be equal.
Not according to SR.
If you are talking about the predictions of a different
theory than SR, I am not interested.
So don't tell me what your theory is.
Je vous remercie de votre réponse, qui clarifie les choses, et montre où nous ne sommes plus d'accord du tout.
On 10/17/2023 3:09 PM, Richard Hachel wrote:
Je vous remercie de votre réponse, qui clarifie les choses, et montre où >> nous ne sommes plus d'accord du tout.
Why are you telling Paul that his hovercraft is full of eels?
He uses the theory as it is taught in universities, but not as I think
it should be taught.
R.H.
He uses the theory as it is taught in universities, but not as I think it should be taught.
Time can change in two ways.
If it slows down it can speed back up...
If a space ship speeds up its time slows down.
Why do you keep wasting time posting nonsense to the Net? -- your time
would be MUCH better spent studying and learning about physics.
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