Consider two clocks approaching (or separating) at relative velocity |v|. According to the Tom Roberts (and Legion?) interpretation of the relativistic doppler, observers riding on those clocks will always measure the other's clock to
be at rest, even as v approaches c, each clock will appear to tic a the same rate
as the other. Consequently, for any observer and any clock, no distinction can be
made between a moving clock and a clock at rest--even as the clock's velocity approaches c.
Le 03/09/2023 à 23:04, patdolan a écrit :Doctor Hachel, This post got away from me before my thinking was fully formed. I disown it. More later.
Consider two clocks approaching (or separating) at relative velocity |v|. According to the Tom Roberts (and Legion?) interpretation of the relativistic
doppler, observers riding on those clocks will always measure the other's clock to
be at rest, even as v approaches c, each clock will appear to tic a the same rate
as the other. Consequently, for any observer and any clock, no distinction can be
made between a moving clock and a clock at rest--even as the clock's velocity
approaches c.
"There is no absolute frame of reference. The laws of physics are always
the same when there is a change of frame of reference,
and the effects of this physics are always reciprocal by permutation of frame of reference"
Several observers evolving at very different relative speeds will never be able to agree on the fact that one of them
moves faster or slower than the other in a possible ether.
If we take an terrestrial observer, and an observer moving almost at the speed of light (0.9999c): for the other observer, there is no doubt that
it is the earth which is moving at 0.9999c.
There is no solution to this, and we cannot change it.
The universe is made like that.
R.H.
Consider two clocks approaching (or separating) at relative velocity
|v|. According to the Tom Roberts (and Legion?) interpretation of
the relativistic doppler, observers riding on those clocks will
always measure the other's clock to be at rest, even as v approaches
c, each clock will appear to tic a the same rate as the other.
Consequently, for any observer and any clock, no distinction can be
made between a moving clock and a clock at rest--even as the clock's
velocity approaches c.
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