On Wednesday, 23 October 2019 at 07:36:16 UTC+11, Dr. Jai Maharaj wrote:

In article
<8c8a800b-50c1-410b...@googlegroups.com>,
Arindam Banerjee <banerjee...@gmail.com> posted:

The physics aphorisms of Arindam

1.1 While relativity is completely wrong, such cannot be
said of quantum theory.

1.2 However it depends upon energy levels of the orbital
electrons. It ignores the existence of aether. It is devoid
of any geometric basis for electron movement.

1.3 Depending upon energy levels to begin with is perilous.
Energy is for business and money-making -- the physicist
should be interested primarily about forces. And as force
unlike power/energy is a vector quantity, and so has
direction, the geometrical situation is of paramount
importance.

1.4 Using quantum theory, reflection of light may be
explained this way -- an incoming packet of energy called a
photon causes an electron to jump from a lower energy
orbital shell to a higher energy orbital shell. This is
unstable, so it jumps down from the higher energy orbital
shell to the lower energy orbital shell. The difference in
energy is emitted now as a photon.

1.5 In 1.4 above the implicit notion is that the electron
orbits are circular. It is also implied that the photon
must have some mass as it has energy following e=mcc, and
this mass with movmentum mc has the energy to kick up the
electron to the higher orbit shell.

1.6 Now let us consider the above phenomenon in terms of
aether, forces and geometries.

1.7 Aether by definition is a very fine solid through which
all protons and electrons and neutrons pass the way bullets
may go through grass which does not break but just bends.
The photon in the aetheric context is a small burst of
radiant energy. It is a disturbance with no mass.

1.8 When this aetheric disturbance caused by the radiation
reaches the electron and as it envelops the electron, it
changes the orbit of the electron by displacement.

1.9 In the process of displacement the disturbance loses
its energy as the force to displace the electron is lost
with the movement of the electron. This is for the first
quarter cycle of the wave -- from zero to peak

1.10 As a result of the energy absorption the orbit of the
electron is no longer circular but elliptical, and more
"high energy" that way.

1.11 An electric field is created with the dipole effect
caused by the elliptic orbit. There was no electric field
before the disturbance; now there is; so there has been a
change of electric field meaning that has to be a
corresponding changing magnetic field. Which will creating
another changing electric field and so on till we have a
burst of radiation, equivalent to the photon.

1.12 The electron at the higher energy level or greater
ellipticity can be returned to the original orbit shell
with the next quarter of the wave, from peak to zero.
Again, as per 1.11 there will be a electromagnetic wave
formation completing the half cycle.

1.13 The electron in this case does not behave as a single
orbiting particle but as a thin and elastic rubber band.

1.14 The idea of the electron not as a particle but as a
rubber band is of crucial importance in our study of he
nucleus of an atom.

2.1 Aether, a solid made of infinitely fine particles,
fills the entire infinite universe.

2.2 The particles can vibrate, that is, oscillate about
their mean positions.

2.3 The only force in the universe is electric as matter is
made up of positive and negative charges.

2.4 When the electric field changes, it creates a changing
magnetic field, which creates a changing electric field and
so on. The changing electric fields vibrate the aether.

2.5 If the electric field loops as in a current, there is a
steady magnetic field.

2.6 Matter is made up of negative charges called electrons
and protons that are positive charges.

2.7 Under mutual attraction, they go through aether as a
diver through a wave. When static, they let the wave push
them this way and that.

2.8 Aether is a solid but its density cannot be found as
aether fills everything including the space within the
atom.

2.9 Only the density of protons and electrons can be
estimated, for their mass and volume may be known from
experiments.

2.10 Aether cannot affect the normal movement of the
electrons and protons as they go through aether. There is
no drag.

2.11 Aether bends to let electrons and protons squeeze
through. No loss of momentum, thus, in the normal
situation.

2.11 But with the applies electric field there is aetheric
swaying from vibration about their mean positions
according to the frequency of the changing electric field.
This is what moves the electrons from their normal states.
In this displacement of the electron the kinetic energy of
the electromagnetic wave is absorbed.

2.12 Thus only when there is an electric field causing
vibration to the aether there is momentum transfer to the
electron.

2.13 Electrons are like rubber bands while protons may be
spherical.

3.1 The aether particles are infinitely small by
definition.

3.2 As they are infinitely small like points they have as
you say no shape nor structure not volume.

3.3 Under the impact of electrical forces they vibrate and
this vibration impacts upon the momentum of the electrons.

3.4 Thus the kinetic energy of the vibration transforms to
the kinetic energy of the electron.

3.5 The reverse situation happens when the electron loses
its kinetic energy. It creates the aetheric vibration.

3.6 This is understood it as water molecules going past a
very thin set of wires forming a sieve. Only this time the
water molecules stick to each other in their relative
positions.

3.7 Aether particles bend aside to let the electrons and
protons pass through them.

4.1 The definition of aether follows from a book referred
to and quoted from in my 2005 post.'

https://groups.google.com/d/msg/soc.culture.australian/wwQ4LkfM4bc/7uhLA2kLDfQJ

4.2 aether: a solid where infinitely fine, infinitely
elastic particles filling the entire infinite universe
including the inter-atomic spaces maintain their respective
positions. It is the medium for the propagation of energy
with electromagnetic waves.

4.3 The 19th century notions of aether are extended to
explain the propagation of electromagnetic waves acting
upon the electrons in matter; and how matter receives these
waves and creates these waves. This is the field approach
where forces with their directions are given primary
importance.

4.4 This is a far superior and intuitive approach than its
alternative, the energy based quantum theory which depends
solely upon assumptions piled upon assumptions.

5.1 Consider a firecracker -- the amount of gunpowder is
small as compared to the amount of packing. When the
cracker explodes, the paper or string is blown out. It is
supposed that the energy of the firecracker comes from the
powder alone. For the string or paper surrounding the
powder is chemically inert.

5.2 The above fact, that packing is needed for powerful
explosions, was very well known to all those using muzzle
loader guns. They had to pack the powder in.

5.3 That loose powder does not explode, merely burns well,
is also clearly shown by the behaviour of fuses.

5.4 If we go by the calorie output of fuses and crackers,
we should get the same result.

5.4 However firecrackers, bombs, etc. that require a lot of
packing (paper or steel casing) produce a lot more kinetic
energy than the fuse.

5.5 This kinetic energy is evidently coming from the
packing.

5.6 Tighter the packing, greater the energy.

5.7 These are some of the basic issues, observed from
Nature, that will be useful to understand the formula of
energy creation and destruction, namely 0.5mVVN(N-k).

6.1 Let a mass m in free space have within its geometry an
internal energy source that can increase its velocity by an
amount v each time an amount of energy k.E from it is
utilised. The kinetic increases after each hit increases by
E = 0.5mvv. k is an efficiency factor greater than 1
related to the losses involved in converting the internal
energy to the kinetic energy. After N hits the velocity
will be Nv. With respect to the initial state the kinetic
energy of the mass will be 0.5mvvNN. The internal energy
used up will be NkE or 0.5mvvNk. Thus the increase in
energy e after N hits will be, if N>k, e=0.5mvvN(N-k).

6.2 The most obvious display of internal energy creating
internal force equally in directions is the chemical
explosion. A matchstick, a bullet, a chemical bomb -- these
are all examples of chemical explosion showing the
utilisation of internal energy used for creating internal
force, that causing heat and kinetic energy to the
surroundings.

6.3 Aphorisms 5.1 to 5.7 (given below) elaborate on the
nature of the explosion in relation to the energy
generated, with respect to packing of the explosive matter.

6.4 The nuclear explosion creates a great deal more
destructive kinetic energy than a chemical explosion. This
is because the packing in a nuclear explosion is much more
dense than a chemical reaction. In a chemical reaction
atoms are involved. In a nuclear reaction the nucleus is
involved.

6.5 In quantitative terms, the dimension of an atom is of
the order of 10^-10m; the dimension of the nucleus is of
the order of 10^-15m or 10^5 times more. This is the linear
dimension -- in three dimensions the packing of nuclei will
be denser by a factor of 10^15. However in a nuclear
explosion it is not as if all the atoms are bunched up as
nuclei -- so the packing factor is in between 10^5 to
10^15. Let us say that a nuclear explosion the active
constituents are packed to the order of 10^6 with respect
to the chemical explosion to be conservative.

6.6 From the above rough analysis, it is obvious that the
nuclear explosion, for the same mass, should be 10^10 times
more powerful than the chemical explosion. 1 ton of TNT
generates 5*10^9 joules; a nuclear bomb of mass 1 ton of
active material (the nuclear material plus the packing
surrounds) should thus generate 5*10^15 joules. Now a
hydrogen bomb of 1 Megaton generates 5*10^15 joules.

6.7 Thus the simple matter of packing the fissile material
explains the vast disparity of energy between the nuclear
explosion and the chemical explosion.

6.8 What is happening is that the N factor in the equation
e=0.5mvvN(N-k) is much higher for the nuclear explosion
than it is for the chemical. Each atom in m gets hit N
times in any explosion -- greater the packing, more the N.
The outer atoms get hit by inner atoms that are getting out
in all directions, again and again. The force is directed
in all directions; the non-fissile elements get hit by the
fissile atoms that keep on expanding out at a great
velocity.

7.0 About the hydrogen bomb, and how the so-called strong
nuclear force is actually the familiar electrostatic force
operating at the atomic nucleus level.

7.1 The hydrogen atom is composed of a single proton and a
single electron circling around it, as per the most
established model of the hydrogen atom. There are isotopes
of hydrogen occuring naturally -- there is a neutron
associated with that single proton. It is this isotope --
deuterium -- of hydrogen that is used in nuclear bombs
(called hydrogen bombs, based upon supposed fusion).

7.2 In fusion, the deuterium is supposed to become another
isotope -- tritium -- after intense heat is applied as a
result of an earlier fission bomb. There is apparently a
drop in mass, that is translated into energy. However, we
can propose another alternative explanation for this great
energy.

7.3 Consider a neutron to be a close union of a proton and
an electron. The bond between them is extraordinarily
strong -- two charges joined at a zero distance, so the
bonding force is very great. However, let us assert that
the electron does not lose its identity even in this close
union.

7.4 A deuterium atom can thus be seen as the union of two
protons joined by an electron. The bonding force here is
very strong, but can be broken with enormous impact is
caused as a result of nuclear fission.

7.5 Nuclear fission causes the extraordinary aether
vibration to break apart the bonding in the deuterium atom.
The two protons in the nucleus cannot be held together by
the electron. As the electron gives up its hold, the two
protons, that are at a very close distance, move apart with
extraordinary force.

7.6 The movement of the protons with respect to the
electron causes a time varying electric field, which will
create a time varying magnetic field, and together they
will proceed as a very high energy electromagnetic gamma
ray once again causing aetheric vibration. This vibration
will dissociate the other deuterium atoms, causing a chain
reaction. Being very fast, and very powerful with the most
extrordinary electrostatic forces being released, the
hydrogen bomb is thus created.

7.7 The hydrogen bomb thus has nothing to do with fusion,
but with the fission of the deuterium isotope of hydrogen.

7.8 The deuterium isotope may be considered the fundamental
building block for the nuclei of all other elements.
Multiples of them, with extra neutrons, constitute the
nuclei of the heavier elements. The electrons glue the
protons together, while presenting a net positive charge
that are balanced by the electrons orbiting the nucleus.

Dhanyavaad for your post.

Jai Maharaj, Jyotishi Om Shanti http://groups.google.com/group/alt.fan.jai-maharaj

Incredible the design of the Lord!

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)