• pressure variations

    From Uno Qualunque@21:1/5 to All on Wed Aug 3 06:29:30 2022
    Hi

    inside a sphere buried within a elastic ideal medium at pressure P1 I
    create a variation of pressure of dP. What variation dPx I would measure
    if the sphere was buried in a medium at pressure P2 using the same
    energy? Is it possible to solve this problem?

    Sorry I'm not a physicist

    Thank you

    Jen

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  • From Richard Livingston@21:1/5 to Jen on Wed Aug 3 17:26:45 2022
    On Wednesday, August 3, 2022 at 1:29:34 AM UTC-5, Jen wrote:
    Hi

    inside a sphere buried within a elastic ideal medium at pressure P1 I
    create a variation of pressure of dP. What variation dPx I would measure
    if the sphere was buried in a medium at pressure P2 using the same
    energy? Is it possible to solve this problem?

    Sorry I'm not a physicist

    Thank you

    Jen

    Jen,

    There is not enough information to give a complete answer, or perhaps
    I don't understand exactly what you are describing. If by "elastic ideal medium" you mean an ideal gas, and by "a sphere buried within" you
    mean a bubble (i.e. no shell or balloon skin that would affect the size
    and stiffness of the sphere) then the problem is no different than an
    ideal gas in a cylinder being held a constant pressure. However in
    that case the pressure would remain constant as the volume of the
    bubble increases. That is, you would not be able to increase the
    pressure.

    If instead you mean a rapid ("instantaneous") increase in pressure
    inside the sphere, then the work would be dW = VdP, where V is the
    initial volume of the bubble. But then the bubble would start to
    expand until its pressure returned to the ambient.

    If by "elastic ideal medium" you mean a solid, then you must know
    the stiffness of the solid as the spherical hole will expand somewhat
    as the pressure is increased. That expansion will take some work
    (energy).

    I'm not sure if any of that is a useful answer to you. Depending on
    exactly what your problem is this can be quite complicated.

    Rich L.

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