• Time in accelerated reference frames

    From Luigi Fortunati@21:1/5 to All on Tue May 31 07:54:31 2022
    In accelerated reference frames, the clocks do not stay synchronized
    with each other.

    Yet on Earth, which is an accelerated reference frame, all the clocks
    that are at the same altitude remain perfectly synchronized with each
    other wherever they are, why?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From J. J. Lodder@21:1/5 to Luigi Fortunati on Tue May 31 10:48:48 2022
    Luigi Fortunati <fortunati.luigi@gmail.com> wrote:

    In accelerated reference frames, the clocks do not stay synchronized
    with each other.

    Yet on Earth, which is an accelerated reference frame, all the clocks
    that are at the same altitude remain perfectly synchronized with each
    other wherever they are, why?

    No. They don't.
    It is just that the gravitational effects of the sun can be ignored.
    (with the available precision)
    Remember that the radius of the Earth
    is very small on the scale of the AU.

    Jan

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Tom Roberts@21:1/5 to Luigi Fortunati on Wed Jun 1 18:33:47 2022
    On 5/31/22 2:54 AM, Luigi Fortunati wrote:
    In accelerated reference frames, the clocks do not stay synchronized
    with each other.

    Hmmm. Clocks that are at the same "altitude" relative to the
    acceleration do remain synchronized.

    Note also that "accelerated frame" is an oxymoron -- "frame" implies a
    set of four mutually-orthogonal coordinate axes, which can occur ONLY
    for inertial coordinates.

    Yet on Earth, which is an accelerated reference frame,

    No, it is not. On the surface of the earth, a "small" region of
    spacetime can be considered to be equivalent to an accelerated system in
    flat spacetime, but larger regions on the surface are nowhere close to
    an accelerated system in flat spacetime. Here "small" depends on one's measurement accuracy.

    all the clocks that are at the same altitude remain perfectly
    synchronized with each other wherever they are, why?

    Because in weak gravity, "gravitational time dilation" depends on the gravitational potential, which primarily depends on altitude (as in an accelerated system in flat spacetime). This is only approximate: when
    measured very accurately, the potential at a given altitude depends on
    the density of the material below, and on the positions of sun, moon,
    and planets above -- at 15,000 feet above earth's geoid, the potential
    over Pike's Peak is measurably different from that over Death Valley.

    Tom Roberts

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From J. J. Lodder@21:1/5 to Tom Roberts on Wed Jun 8 21:51:11 2022
    Tom Roberts <tjroberts137@sbcglobal.net> wrote:

    On 5/31/22 2:54 AM, Luigi Fortunati wrote:
    In accelerated reference frames, the clocks do not stay synchronized
    with each other.

    Hmmm. Clocks that are at the same "altitude" relative to the
    acceleration do remain synchronized.

    Note also that "accelerated frame" is an oxymoron -- "frame" implies a
    set of four mutually-orthogonal coordinate axes, which can occur ONLY
    for inertial coordinates.

    Yet on Earth, which is an accelerated reference frame,

    No, it is not. On the surface of the earth, a "small" region of
    spacetime can be considered to be equivalent to an accelerated system in
    flat spacetime, but larger regions on the surface are nowhere close to
    an accelerated system in flat spacetime. Here "small" depends on one's measurement accuracy.

    all the clocks that are at the same altitude remain perfectly
    synchronized with each other wherever they are, why?

    Because in weak gravity, "gravitational time dilation" depends on the gravitational potential, which primarily depends on altitude (as in an accelerated system in flat spacetime). This is only approximate: when measured very accurately, the potential at a given altitude depends on
    the density of the material below, and on the positions of sun, moon,
    and planets above -- at 15,000 feet above earth's geoid, the potential
    over Pike's Peak is measurably different from that over Death Valley.

    Certainly, but one should realise that there is no such thing
    as an absolute value of the Newtonian potential.
    It depends on which masses you consider to be relevant,
    at your level of approximation.
    Or in other words, where you consider a practical 'at infinity' to be.

    Fortunati says correctly that all clocks on a Newtonian equipotential
    system, calculated with respect to all masses on the Earth,
    will remain synchronised. (for all practical purposes, on Earth)
    But they will not remain synchronised when you also consider
    the (as yet unobservably small) gravitational effects of the Sun
    at diferent places on Earth.

    In practical terms, for all 'sub-lunar' calculations
    the relativistically corrected TCG timescale will do.
    (which takes only terrestrial relativistic corrections into account)
    If you want to go further out in the Solar system you need TCB,
    which corrects for solar gravitational effects.

    BTW, for practical purposes all those relativistic time scales
    are computed as corrections to TAI,

    Jan

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)