In my animation
https://www.geogebra.org/m/qc9pfvva
there is the force of gravity <mg> (in black), the component parallel
to the plane (in blue) and the other component perpendicular to the
plane (in red).
Starting the animation, as the inclination of the plane increases, the vertical force of gravity (in black) remains unchanged and the force perpendicular to the plane (in red) decreases to zero.
Is it correct to say that as the inclination of the plane increases,
the red force disappears but the black force does not disappear at all?
[[Mod. note -- For anyone unable to view the animation, it shows a block
on an inclined plane (at an angle $\alpha$ to the horizontal), with the block's weight $mg$ (shown in black) resolved into components
$mg \cos \alpha$ perpendicular to the plane (shown in red)
and $mg \sin \alpha$ parallel to the plane (shown in blue).
To answer the author's question: yes, the black force (the block's weight $mg) is unchanged as the inclination of the increases, but the red force
(the component $mg \sin \alpha$ perpendicular to the plane) decreases.
When the inclination reaches 90 degrees then the red force is zero.
-- jt]]
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