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  • Nice simple parsing problem but watch out: A+((B*C))+D => A+(B*C)+D and

    From Charlie-Boo@21:1/5 to All on Wed Sep 13 05:44:53 2023
    Shortest algorithm to translate all instances of:

    A+((B*C))+D => A+(B*C)+D
    A*(B)+C => A*B+C

    C-B

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