Seems like they're doing some kind of tanh interpolation but it's not entirely obvious to me how they get from equation (3) to the expression
in (5).
bitrex wrote:
<snip>
Seems like they're doing some kind of tanh interpolation but it's not
entirely obvious to me how they get from equation (3) to the expression
in (5).
Unless the fuzzy form of your scan deceives my eyes, it appears the
numerator and denominator are multiplied by the conjugate to obtain
(4) from (3).
A clearer scan may enable me to continue.
Danke,
bitrex wrote:
<snip>
Seems like they're doing some kind of tanh interpolation but it's not
entirely obvious to me how they get from equation (3) to the expression
in (5).
Unless the fuzzy form of your scan deceives my eyes, it appears the
numerator and denominator are multiplied by the conjugate to obtain
(4) from (3).
A clearer scan may enable me to continue.
Danke,
Don wrote:
bitrex wrote:
<snip>
Seems like they're doing some kind of tanh interpolation but it's not
entirely obvious to me how they get from equation (3) to the expression
in (5).
Unless the fuzzy form of your scan deceives my eyes, it appears the
numerator and denominator are multiplied by the conjugate to obtain
(4) from (3).
A clearer scan may enable me to continue.
Danke,
(not sure if my response posted as I don't see it on my newsreader,
apologies if this reply appears twice)
Sure, here's the full page in question:
<https://imgur.com/a/as3jfNo>
I have a hardcopy from an academic library which is a relatively massive (800+) page tome so difficult to get a good scan of...the only full-text online I can find is on Springerlink (blech) and despite my having an "institutional login" that should grant access to it. it never seems to
work with them.
bitrex wrote:
Don wrote:
bitrex wrote:
<snip>
Seems like they're doing some kind of tanh interpolation but it's not
entirely obvious to me how they get from equation (3) to the expression >>>> in (5).
Unless the fuzzy form of your scan deceives my eyes, it appears the
numerator and denominator are multiplied by the conjugate to obtain
(4) from (3).
A clearer scan may enable me to continue.
Danke,
(not sure if my response posted as I don't see it on my newsreader,
apologies if this reply appears twice)
Sure, here's the full page in question:
<https://imgur.com/a/as3jfNo>
I have a hardcopy from an academic library which is a relatively massive
(800+) page tome so difficult to get a good scan of...the only full-text
online I can find is on Springerlink (blech) and despite my having an
"institutional login" that should grant access to it. it never seems to
work with them.
Your first followup was indeed posted.
The first three steps from (4) to (5) are easy-peasy:
tanh(s) = (e^s - e^-s) / (e^s + e^-s)
H(s) = Q(s) / D(s) = (e^s - e^-s) / (e^s + e^-s)
(e^s + e^-s)Q(s) = (e^s - e^-s)D(s)
Control Theory must now be reviewed by me in order to continue.
# # #
"Lecture Notes in Control and Information Sciences" seems to be a series
of books, each about three hundred pages long. Where do you find page
808?
Danke,
even and odd parts in (4), I think plugging that form into
tanh(arctan(z)) = (e^z - e^-z) / (e^z + e^-z)
On 6/11/2024 11:17 PM, Don wrote:
bitrex wrote:
Don wrote:
bitrex wrote:
<snip>
Seems like they're doing some kind of tanh interpolation but it's not >>>>> entirely obvious to me how they get from equation (3) to the
expression
in (5).
Unless the fuzzy form of your scan deceives my eyes, it appears the
numerator and denominator are multiplied by the conjugate to obtain
(4) from (3).
A clearer scan may enable me to continue.
Danke,
(not sure if my response posted as I don't see it on my newsreader,
apologies if this reply appears twice)
Sure, here's the full page in question:
<https://imgur.com/a/as3jfNo>
I have a hardcopy from an academic library which is a relatively massive >>> (800+) page tome so difficult to get a good scan of...the only full-text >>> online I can find is on Springerlink (blech) and despite my having an
"institutional login" that should grant access to it. it never seems to
work with them.
Your first followup was indeed posted.
The first three steps from (4) to (5) are easy-peasy:
tanh(s) = (e^s - e^-s) / (e^s + e^-s)
H(s) = Q(s) / D(s) = (e^s - e^-s) / (e^s + e^-s)
(e^s + e^-s)Q(s) = (e^s - e^-s)D(s)
Control Theory must now be reviewed by me in order to continue.
Thanks, I think I see sorta see how (5) is derived now. I believe they
mean by their notation tanh(phi(s)) and phi(s) = arctan(Q(s)/D(s)).
The denominator of (4) will be real, and the portions of the numerator
that are an even function times an even function will be real and the
parts that are anything else will be imaginary
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