I have the exact same Unisaw. I connect my saw to my 30 amp dryer connector via a 30 amp twist lock converter and I have never experienced any issue.
I also have a 24" 5hp delta x5 planner that I also connect through my dryer outlet and also have never had an issue.
In article <1078204646.761648@smirk>, <_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240V
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are ratedUsing Ohm's law this is a relatively simple question to answer...
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow" breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrobertdavis@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >>> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow"
breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
Sure it does, for RMS volts and amps, and pure resistances (like metal
wires and components).
Motors and inductors and capacitors are a different kettle of fish. An >ordinary ohmmeter measures DC resistance, which for an inductor is the >resistance of the copper wire winding, but AC current and voltage are >connected by AC reactance., which will be far larger than the DC
resistance at the usual operating frequency of that inductor.
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the
startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow"
breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:Yes it does - the R just means reactance instead of resistance -
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the
startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow"
breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob DavisYou will want a "high magnetic" breaker - which, fortunately for you
<wrobertdavis@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >>> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow"
breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
Sure it does, for RMS volts and amps, and pure resistances (like metal
wires and components).
Motors and inductors and capacitors are a different kettle of fish. An >ordinary ohmmeter measures DC resistance, which for an inductor is the >resistance of the copper wire winding, but AC current and voltage are >connected by AC reactance., which will be far larger than the DC
resistance at the usual operating frequency of that inductor.
Joe Gwinn
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow"
breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.Yes it does - the R just means reactance instead of resistance -
wheather inductive or capacitive. With resistive loads it's the same
as with DC - read the resistance on your ohm-meter. With "inductive
loads" the reactance will always be higher than the resistance (draws
less current)
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob DavisYou are right in the theory. In practice, doing calculations about motor current with simple ohm's law does not work because a motor is not a pure resistive load.
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated
at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow"
breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.Sure it does, for RMS volts and amps, and pure resistances (like metal
wires and components).
Motors and inductors and capacitors are a different kettle of fish. An ordinary ohmmeter measures DC resistance, which for an inductor is the resistance of the copper wire winding, but AC current and voltage are connected by AC reactance., which will be far larger than the DC
resistance at the usual operating frequency of that inductor.
Joe Gwinn
What is a real world example of purely resistive load supplied by AC?
On Monday, November 8, 2021 at 8:28:53 PM UTC-6, Clare Snyder wrote:
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:Yes it does - the R just means reactance instead of resistance -
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated >> >> > at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >> >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow" >> >> breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
wheather inductive or capacitive. With resistive loads it's the same
as with DC - read the resistance on your ohm-meter. With "inductive
loads" the reactance will always be higher than the resistance (draws
less current)
What is a real world example of purely resistive load supplied by AC?
On Monday, November 8, 2021 at 8:28:53 PM UTC-6, Clare Snyder wrote:
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:Yes it does - the R just means reactance instead of resistance -
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated >> >> > at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be
borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >> >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow" >> >> breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
wheather inductive or capacitive. With resistive loads it's the same
as with DC - read the resistance on your ohm-meter. With "inductive
loads" the reactance will always be higher than the resistance (draws
less current)
What is a real world example of purely resistive load supplied by AC?
On Wed, 10 Nov 2021 05:22:37 -0800 (PST), Bob Davis
<wrobertdavis@gmail.com> wrote:
On Monday, November 8, 2021 at 8:28:53 PM UTC-6, Clare Snyder wrote:
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:Yes it does - the R just means reactance instead of resistance -
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated >>> >> > at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be >>> >> > borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >>> >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous >>> >> load above 16 amps. It seems to me, that with the proper type of "slow" >>> >> breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
wheather inductive or capacitive. With resistive loads it's the same
as with DC - read the resistance on your ohm-meter. With "inductive
loads" the reactance will always be higher than the resistance (draws
less current)
What is a real world example of purely resistive load supplied by AC?
I believe an oven or (non-induction) stove would come pretty close.
On Monday, November 8, 2021 at 8:28:53 PM UTC-6, Clare Snyder wrote:
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated >> > at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be >> > borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous
load above 16 amps. It seems to me, that with the proper type of "slow" >> breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
What is a real world example of purely resistive load supplied by AC?Ohm's law is for DC. It does not apply to AC.Yes it does - the R just means reactance instead of resistance -
wheather inductive or capacitive. With resistive loads it's the same
as with DC - read the resistance on your ohm-meter. With "inductive
loads" the reactance will always be higher than the resistance (draws
less current)
On Wed, 10 Nov 2021 05:22:37 -0800 (PST), Bob Davis99% close enough? A baseboard heater or any calrod heater, an
<wrobertdavis@gmail.com> wrote:
On Monday, November 8, 2021 at 8:28:53 PM UTC-6, Clare Snyder wrote:
On Mon, 8 Nov 2021 16:07:24 -0800 (PST), Bob Davis
<wrober...@gmail.com> wrote:
On Tuesday, March 2, 2004 at 6:20:32 AM UTC-6, Joe McDonald wrote:Yes it does - the R just means reactance instead of resistance -
In article <1078204646.761648@smirk>,
<_firstname_@lr_dot_los-gatos_dot_ca.us> wrote:
What amperage breaker does one need for a 5HP table saw on a 240VUsing Ohm's law this is a relatively simple question to answer...
single phase circuit?
My logic: Typically, single phase 5HP 240V (or 230V) motors are rated >>> >> > at 19.8 or 20 A. Given that a circuit is supposed to be loaded 80%
(look it up in the NEC sometime), this means a 25 A breaker would be >>> >> > borderline sufficient, and that a 30A breaker should be generous.
With a slow breaker (not a fuse), there should be no problems with the >>> >> > startup surge of the motor tripping the breaker.
1 horsepower = 745.7 watts
Power (watts) = I (amperage) x E (voltage)
When you have two values for the variables in the equation you can
figure out the third.
P 3728.5 (watts 1 HP x 5)
Therefore I = --- or I = ------
E 230 volts
230 volts = 16.21 amps
240 volts = 15.53 amps
Using the "80% rule", a 20 amp breaker should not exceed a continuous >>> >> load above 16 amps. It seems to me, that with the proper type of "slow" >>> >> breaker, you should be OK with a 20 amp breaker.
Joe
PS
I am not an electrician or an electrical engineer. In fact, I have
never even played one on TV.
Ohm's law is for DC. It does not apply to AC.
wheather inductive or capacitive. With resistive loads it's the same
as with DC - read the resistance on your ohm-meter. With "inductive
loads" the reactance will always be higher than the resistance (draws
less current)
What is a real world example of purely resistive load supplied by AC?
I believe an oven or (non-induction) stove would come pretty close.
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