• from ( 4 x 3 sheet ) -- How many Z-stamp combinations can you create ?

    From henhanna@gmail.com@21:1/5 to All on Mon Oct 24 21:23:17 2022
    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped

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  • From Mike Terry@21:1/5 to henh...@gmail.com on Tue Oct 25 14:24:03 2022
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From henhanna@gmail.com@21:1/5 to Mike Terry on Tue Oct 25 09:35:47 2022
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote:
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped



    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)



    ___________________
    Rereading Proust produces a state of mental inertia (6)

    --- SoupGate-Win32 v1.05
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  • From Mike Terry@21:1/5 to henh...@gmail.com on Fri Oct 28 20:43:25 2022
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote:
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped



    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)

    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65

    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula. For a single shape, the formula is simple, but making different
    shapes is not simple...

    If you want to vary just the width/height of the sheet, then the number 65 above varies in the
    obvious way, as the h and v columns adjust, so we could get a simple formula for this (a polynomial
    of degree 2 in W,H), at least for W,H >= 4. (For smaller W,H, some shapes may not fit at all,
    complicating things.)

    Mike.
    ps. there may be silly mistakes in above calculation!

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  • From henhanna@gmail.com@21:1/5 to Mike Terry on Fri Oct 28 13:19:47 2022
    On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote:
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote:
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped



    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65

    i got 65 too.


    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.



    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Mike Terry@21:1/5 to henh...@gmail.com on Fri Oct 28 22:24:45 2022
    On 28/10/2022 21:19, henh...@gmail.com wrote:
    On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote:
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote:
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped >>>>>


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as >>> e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65

    i got 65 too.


    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.



    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?


    You can work it out if you like - just adjust all the calculation lines above by upping the h and v
    columns appropriately. E.g. for the xxxx line, the new line will be

    h v rr Tot

    old xxxx : 1 x 3 x 1 = 3
    new xxxx : 37 x 30 x 1 = 1110

    You have increased the width,height each by a factor of 10. Each such scaling will increase the Tot
    column by a factor of (typically) a bit more than 10, so the new answer will be more than 6500.

    Considering the number as a fraction of the total number of stamps, the fraction will tend to a
    limit as the width/height of the stamp block increases. The limit is determined by adding all the
    rr values in the calculation columns, which essentially gives the total number of distinct "shapes"
    [*] that can be made out of the connected stamps. Perhaps you're really more interested in the
    problem of how many such shapes can be made.

    [*] "distinct shapes" means shapes ignoring duplicates resulting from reflections/rotations/translations.

    Mike.

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  • From Ilan Mayer@21:1/5 to henh...@gmail.com on Sat Oct 29 06:42:07 2022
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote:
    On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote:
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote:
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped >>>


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?

    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    For 40 x 30 this gives 20,873

    Please reply to ilanlmayer at gmail dot com

    __/\__
    \ /
    __/\\ //\__ Ilan Mayer
    \ /
    /__ __\ Toronto, Canada
    /__ __\
    ||

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Ilan Mayer@21:1/5 to Ilan Mayer on Sat Oct 29 10:54:04 2022
    On Saturday, October 29, 2022 at 9:42:09 AM UTC-4, Ilan Mayer wrote:
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote:
    On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote:
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote:
    On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped >>>


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?
    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    This can be simplified into 19*n*m-28*n-28*m+33

    For 40 x 30 this gives 20,873

    Please reply to ilanlmayer at gmail dot com

    __/\__
    \ /
    __/\\ //\__ Ilan Mayer
    \ /
    /__ __\ Toronto, Canada
    /__ __\
    ||

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Mike Terry@21:1/5 to Ilan Mayer on Sat Oct 29 19:08:43 2022
    On 29/10/2022 18:54, Ilan Mayer wrote:
    On Saturday, October 29, 2022 at 9:42:09 AM UTC-4, Ilan Mayer wrote:
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote: >>> On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote:
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote: >>>>>> On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped >>>>>>>


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as >>>>> e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?
    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    This can be simplified into 19*n*m-28*n-28*m+33

    Right - a 2nd degree polynomial in m,n.

    As m,n increase (together), the 19*m*n term dominates, and the result, divided by n*m (number of
    stamps) converges to 19.

    19 is the number of essentially different shapes we can make with 4 connected stamps.

    Mike.


    For 40 x 30 this gives 20,873

    Please reply to ilanlmayer at gmail dot com

    __/\__
    \ /
    __/\\ //\__ Ilan Mayer
    \ /
    /__ __\ Toronto, Canada
    /__ __\
    ||

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From henhanna@gmail.com@21:1/5 to Mike Terry on Sat Oct 29 16:19:43 2022
    On Saturday, October 29, 2022 at 11:08:48 AM UTC-7, Mike Terry wrote:
    On 29/10/2022 18:54, Ilan Mayer wrote:
    On Saturday, October 29, 2022 at 9:42:09 AM UTC-4, Ilan Mayer wrote:
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote: >>> On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote:
    On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote: >>>>>> On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped >>>>>>>


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?
    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    This can be simplified into 19*n*m-28*n-28*m+33


    so for (40 x 30) sheet... the ans. is 20,873


    Right - a 2nd degree polynomial in m,n.

    As m,n increase (together), the 19*m*n term dominates, and the result, divided by n*m (number of
    stamps) converges to 19.

    19 is the number of essentially different shapes we can make with 4 connected stamps. Mike.


    i'm counting 18 shapes.... maybe there's a good explanation for why it's 19 (and 28)

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From henhanna@gmail.com@21:1/5 to henh...@gmail.com on Sat Oct 29 16:48:47 2022
    On Saturday, October 29, 2022 at 4:19:45 PM UTC-7, henh...@gmail.com wrote:
    On Saturday, October 29, 2022 at 11:08:48 AM UTC-7, Mike Terry wrote:
    On 29/10/2022 18:54, Ilan Mayer wrote:
    On Saturday, October 29, 2022 at 9:42:09 AM UTC-4, Ilan Mayer wrote:
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote:
    On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote: >>>> On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote: >>>>>> On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped



    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?
    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    This can be simplified into 19*n*m-28*n-28*m+33
    so for (40 x 30) sheet... the ans. is 20,873
    Right - a 2nd degree polynomial in m,n.

    As m,n increase (together), the 19*m*n term dominates, and the result, divided by n*m (number of
    stamps) converges to 19.

    19 is the number of essentially different shapes we can make with 4 connected stamps. Mike.


    i'm counting 18 shapes.... maybe there's a good explanation for why it's 19 (and 28)


    How many 2-stamp combinations can you create ?

    2 shapes. CC (Converging Coefficient) is 2



    How many 3-stamp combinations can you create ?

    6 shapes.

    the CC (Converging Coefficient) must be 6 or 7.

    --------------- i'd guess 7.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Mike Terry@21:1/5 to henh...@gmail.com on Sun Oct 30 01:45:59 2022
    On 30/10/2022 00:19, henh...@gmail.com wrote:
    On Saturday, October 29, 2022 at 11:08:48 AM UTC-7, Mike Terry wrote:
    On 29/10/2022 18:54, Ilan Mayer wrote:
    On Saturday, October 29, 2022 at 9:42:09 AM UTC-4, Ilan Mayer wrote:
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote: >>>>> On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote: >>>>>> On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote: >>>>>>>> On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped >>>>>>>>>


    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted.

    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?
    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    This can be simplified into 19*n*m-28*n-28*m+33


    so for (40 x 30) sheet... the ans. is 20,873


    Right - a 2nd degree polynomial in m,n.

    As m,n increase (together), the 19*m*n term dominates, and the result, divided by n*m (number of
    stamps) converges to 19.

    19 is the number of essentially different shapes we can make with 4 connected stamps. Mike.


    i'm counting 18 shapes.... maybe there's a good explanation for why it's 19 (and 28)

    It might be a mistake on my part - 19 comes from counting all the rr column values in my original table.

    Here's the table again, but I've added the rotated/reflected shapes

    h v rr Tot

    --------------------------------
    xxxx : 1 x 3 x 1 = 3

    --------------------------------
    x : 4 x 0 x 1 = 0
    x
    x
    x

    --------------------------------
    xxx : 2 x 2 x 4 = 16
    x

    x
    xxx

    xxx
    x

    x
    xxx

    --------------------------------
    xx : 3 x 1 x 4 = 12
    x
    x

    xx
    x
    x

    x
    x
    xx

    x
    x
    xx

    --------------------------------
    xxx : 2 x 2 x 2 = 8
    x

    x
    xxx

    --------------------------------
    x : 3 x 1 x 2 = 6
    xx
    x

    x
    xx
    x

    --------------------------------
    xx : 3 x 2 x 1 = 6
    xx

    --------------------------------
    xx : 2 x 2 x 2 = 8
    xx

    xx
    xx

    --------------------------------
    x : 3 x 1 x 2 = 6
    xx
    x

    x
    xx
    x

    So... that's 19 shapes! You must have missed one?


    Mike.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From henhanna@gmail.com@21:1/5 to Mike Terry on Sat Oct 29 18:48:36 2022
    On Saturday, October 29, 2022 at 5:46:07 PM UTC-7, Mike Terry wrote:
    On 30/10/2022 00:19, henh...@gmail.com wrote:
    On Saturday, October 29, 2022 at 11:08:48 AM UTC-7, Mike Terry wrote:
    On 29/10/2022 18:54, Ilan Mayer wrote:
    On Saturday, October 29, 2022 at 9:42:09 AM UTC-4, Ilan Mayer wrote:
    On Friday, October 28, 2022 at 4:19:49 PM UTC-4, henh...@gmail.com wrote:
    On Friday, October 28, 2022 at 12:43:33 PM UTC-7, Mike Terry wrote: >>>>>> On 25/10/2022 17:35, henh...@gmail.com wrote:
    On Tuesday, October 25, 2022 at 6:24:10 AM UTC-7, Mike Terry wrote: >>>>>>>> On 25/10/2022 05:23, henh...@gmail.com wrote:

    ------ pls wait 3+ days (Longer if you find it easy or trivial) before posting answers or hints to the following.



    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?



    Each of the 2,3,4 stamps must be connected by an edge

    for 3-stamp combinations, they'd be horizontal, vertical, or L-shaped



    What do you count as separate combinations? Are rotated/translated combinations distinct?

    Mike.


    we can assume that each stamp in the (X times Y) sheet has a different picture.


    for me ... i'm most curious if there's an answer that comes out simply as
    e.g.
    (x-1)C(z-1) times (y-1)C(z-1)
    Well, if we want a 2x2 square, say, and we have a 4x3 sheet, then we can make 3x2 = 6 such squares.

    All the answers are like that, but we have to appropriately account for rotations/reflections, and
    the different shapes that are included in the set to be counted. >>>>>>
    So... for 4-stamp combinations: (with a 4x3 sheet)

    h v rr Tot

    xxxx : 1 x 3 x 1 = 3

    x : 4 x 0 x 1 = 0
    x
    x
    x

    xxx : 2 x 2 x 4 = 16
    x

    xx : 3 x 1 x 4 = 12
    x
    x

    xxx : 2 x 2 x 2 = 8
    x

    x : 3 x 1 x 2 = 6
    xx
    x

    xx : 3 x 2 x 1 = 6
    xx

    xx : 2 x 2 x 2 = 8
    xx

    x : 3 x 1 x 2 = 6
    xx
    x

    Total: 65
    i got 65 too.
    [ columns: h = horizontal placements, v = vertical, rr = rotations/reflections ]

    If you're saying you would like a simple formula to get the final number 65, there is not going to
    be any such 'simple' formula.
    i'd love to see a simple formula for this (or similar) problem.


    __________________________

    from a 12-square array ( 4 x 3 sheet ) How many 4-stamp combinations can you create ?

    Assuming that the ans. here is 65...


    from a 1200-square array ( 40 x 30 sheet ) How many 4-stamp combinations can you create ?

    ---------- is it bigger or smaller than 6500 ?
    for n x m sheet with n, m >= 3:

    xxxx (n-3)*m+(m-3)*n

    xxx 4*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xxx 2*((n-2)*(m-1)+(n-1)*(m-2))
    x

    xx 2*((n-2)*(m-1)+(n-1)*(m-2))
    xx

    xx (n-1)*(m-1)
    xx

    Total: 8*((n-2)*(m-1)+(n-1)*(m-2))+(n-3)*m+(m-3)*n+(n-1)*(m-1)

    This can be simplified into 19*n*m-28*n-28*m+33


    so for (40 x 30) sheet... the ans. is 20,873


    Right - a 2nd degree polynomial in m,n.

    As m,n increase (together), the 19*m*n term dominates, and the result, divided by n*m (number of
    stamps) converges to 19.

    19 is the number of essentially different shapes we can make with 4 connected stamps. Mike.


    i'm counting 18 shapes.... maybe there's a good explanation for why it's 19 (and 28)
    It might be a mistake on my part - 19 comes from counting all the rr column values in my original table.

    Here's the table again, but I've added the rotated/reflected shapes

    h v rr Tot

    --------------------------------
    xxxx : 1 x 3 x 1 = 3
    --------------------------------
    x : 4 x 0 x 1 = 0
    x
    x
    x
    --------------------------------
    xxx : 2 x 2 x 4 = 16
    x

    x
    xxx

    xxx
    x

    x
    xxx

    --------------------------------
    xx : 3 x 1 x 4 = 12
    x
    x

    xx
    x
    x

    x
    x
    xx

    x
    x
    xx

    --------------------------------
    xxx : 2 x 2 x 2 = 8
    x

    x
    xxx

    --------------------------------
    x : 3 x 1 x 2 = 6
    xx
    x

    x
    xx
    x

    --------------------------------
    xx : 3 x 2 x 1 = 6
    xx
    --------------------------------
    xx : 2 x 2 x 2 = 8
    xx
    xx
    xx

    --------------------------------
    x : 3 x 1 x 2 = 6
    xx
    x

    x
    xx
    x

    So... that's 19 shapes! You must have missed one?


    Mike.


    i'm (was) counting 18 shapes....

    i missed the vertical one because it doesn't fit in the original ( 4 x 3 sheet )

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Ammammata@21:1/5 to All on Wed Nov 2 14:59:48 2022
    henh...@gmail.com presented the following explanation :
    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?

    78

    --
    /-\ /\/\ /\/\ /-\ /\/\ /\/\ /-\ T /-\
    -=- -=- -=- -=- -=- -=- -=- -=- - -=-
    ........... [ al lavoro ] ...........

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Ammammata@21:1/5 to All on Wed Nov 2 15:02:38 2022
    Ammammata explained on 02/11/2022 :
    henh...@gmail.com presented the following explanation :
    from a 12-square array ( 4 x 3 sheet )

    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?

    78

    ops...

    2-stamp 17
    3-stamp 22
    4-stamp 39

    --
    /-\ /\/\ /\/\ /-\ /\/\ /\/\ /-\ T /-\
    -=- -=- -=- -=- -=- -=- -=- -=- - -=-
    ........... [ al lavoro ] ...........

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From henhanna@gmail.com@21:1/5 to Ammammata on Wed Nov 2 12:08:55 2022
    On Wednesday, November 2, 2022 at 7:02:41 AM UTC-7, Ammammata wrote:
    Ammammata explained on 02/11/2022 :
    henh...@gmail.com presented the following explanation :
    from a 12-square array ( 4 x 3 sheet )

    i wonder where this convention of (W x H) --- [Width first] comes from


    How many 2-stamp combinations can you create ?
    How many 3-stamp combinations can you create ?
    How many 4-stamp combinations can you create ?

    78
    ops...

    2-stamp 17
    3-stamp 22
    4-stamp 39


    i 'm getting... ( 17, 34, 65 )


    one more variation would be... (the rest of the sheet stays in One Piece)

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Ammammata@21:1/5 to All on Thu Nov 3 12:32:16 2022
    henh...@gmail.com expressed precisely :
    2-stamp 17
    3-stamp 22
    4-stamp 39


    i 'm getting... ( 17, 34, 65 )

    maybe I didn't get the picture :)

    --
    /-\ /\/\ /\/\ /-\ /\/\ /\/\ /-\ T /-\
    -=- -=- -=- -=- -=- -=- -=- -=- - -=-
    ........... [ al lavoro ] ...........

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Ammammata@21:1/5 to All on Sun Nov 6 08:35:30 2022
    Il giorno Wed 02 Nov 2022 08:08:55p, *henh...@gmail.com* ha inviato su rec.puzzles il messaggio news:00186d10-c37a-4488-84e9- 94872b24f53dn@googlegroups.com. Vediamo cosa ha scritto:

    2-stamp 17
    3-stamp 22
    4-stamp 39


    i 'm getting... ( 17, 34, 65 )



    ok, I didn't take as valid those shapes not orthogonally connected,
    i.e.

    xx
    x
    x

    or

    x
    xx
    x

    or

    x
    xx

    etc

    --
    /-\ /\/\ /\/\ /-\ /\/\ /\/\ /-\ T /-\
    -=- -=- -=- -=- -=- -=- -=- -=- - -=-
    ........... [ al lavoro ] ...........

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)