• "The 6 Riddle" --- is a common variation to make 10 ?

    From henhanna@gmail.com@21:1/5 to All on Fri Jul 8 08:02:01 2022
    is a common variation to make 10 ? ----- that seems too hard.

    except for 4 + 4 + Sqrt(4) = 10
    and 9 9 9 = 10

    _________________________

    Commonly called "The 6 Riddle", it states that all you do is insert the appropriate math symbol between the numbers to equal six.
    Ex:
    1 1 1 = 6
    2 + 2 + 2 = 6
    3 3 3 = 6 etc.

    6 + 6 - 6 = 6

    all the way to 9 9 9 = 6

    I cannot figure out the first set of numbers, so I am asking anyone to help me out.

    __________________________

    is it poss. to do this without using factorial ?

    1 1 1 = 6

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From denkbaar@21:1/5 to henh...@gmail.com on Fri Jul 8 23:39:10 2022
    On 08-Jul-22 17:02:01, henh...@gmail.com wrote:
    is a common variation to make 10 ? ----- that seems too hard.

    except for 4 + 4 + Sqrt(4) = 10
    and 9 9 9 = 10

    (that would be 9 + 9/9 = 10)

    under certain rules: 1 × 1/.1 = 10

    d.

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From henhanna@gmail.com@21:1/5 to denkbaar on Sat Jul 9 07:25:41 2022
    On Friday, July 8, 2022 at 2:39:13 PM UTC-7, denkbaar wrote:
    On 08-Jul-22 17:02:01, henh...@gmail.com wrote:
    is a common variation to make 10 ? ----- that seems too hard.

    except for 4 + 4 + Sqrt(4) = 10
    and 9 9 9 = 10
    (that would be 9 + 9/9 = 10)

    under certain rules: 1 × 1/.1 = 10

    d.


    i like the Dot (Decimal Point) rule.




    https://old.reddit.com/r/mildlyinteresting/comments/q66jb5/i_created_this_puzzle_where_using_only_4_digits/
    I created this puzzle where using only 4 digits (1,2,5,7), only once each,
    you create expressions using any operations that result in each integer from 0 to 100



    Another common variant =======

    -1 = ........

    0 = (4 ÷ 4) - (4 ÷ 4)
    1 = (4 * 4 ÷ 4) / 4
    2 = (4 ÷ 4) + (4 ÷ 4)
    3 = (4 + 4 + 4) / 4
    4 = sqrt(4 * 4) * (4 ÷ 4)
    5 = ((4 * 4) + 4) / 4
    6 = (4! + 4 - 4) / 4
    7 = (sqrt(4 * 4) + 4!) / 4
    8 = ((4 ÷ 4) * 4) + 4
    9 = (4 ÷ 4) + 4 + 4
    10 = (4! + (4 * 4)) / 4

    11 = ........
    12 = ........ ( i got it )

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From denkbaar@21:1/5 to henh...@gmail.com on Sun Jul 17 12:10:30 2022
    On 09-Jul-22 16:25:41, henh...@gmail.com wrote:

    On Friday, July 8, 2022 at 2:39:13 PM UTC-7, denkbaar wrote:
    On 08-Jul-22 17:02:01, henh...@gmail.com wrote:
    is a common variation to make 10 ? ----- that seems too hard.

    except for 4 + 4 + Sqrt(4) = 10
    and 9 9 9 = 10
    (that would be 9 + 9/9 = 10)

    under certain rules: 1 × 1/.1 = 10

    d.


    i like the Dot (Decimal Point) rule.

    (...)

    How about 11 - 1 = 10?

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)