• End at the Begining

    From leflynn@21:1/5 to All on Mon Oct 18 10:06:18 2021
    Simple challenge to create a 26 word list where the starting and ending letters are the same, with one word for each letter of the alphabet. Your score is the total number of letters. If you skip a letter, your score for that letter is 7. Can you get
    under 100 without consulting a dictionary? Let's use the scrabble players' word list.
    L. Flynn

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  • From Richard Heathfield@21:1/5 to leflynn on Mon Oct 18 18:51:12 2021
    I failed to find a solution. Scroll down if you want to learn why.
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    On 18/10/2021 18:06, leflynn wrote:
    Simple challenge to create a 26 word list where the starting and ending letters are the same, with one word for each letter of the alphabet. Your score is the total number of letters. If you skip a letter, your score for that letter is 7. Can you get
    under 100 without consulting a dictionary? Let's use the scrabble players' word list.

    I tried.

    I failed with j, q, u (no, I don't count Ubuntu!), v, and
    x, z. That's 42 penalty points right there. Under 100 is 99 max, less 42
    is 57.

    Use A, I, and O as one-letter words, which means there are 17 words left
    to get with 54 letters. Burn 34 for firsts and lasts, leaving 20 letters
    / 17 words. So we need fourteen three-letter words:

    bob did eye gig huh mum nun pip tat wow

    covers b d e g h m n p t w (and in my view 'gig', 'huh', 'mum' and 'wow'
    are dodgy to say the least),

    leaving these seven:

    c f k l o r s

    We'd have to find three-letter words for four of them and four-letter
    words for the remainder. I don't see it.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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  • From leflynn@21:1/5 to Richard Heathfield on Mon Oct 18 13:50:31 2021
    On Monday, October 18, 2021 at 1:51:14 PM UTC-4, Richard Heathfield wrote:
    I failed to find a solution. Scroll down if you want to learn why.
    On 18/10/2021 18:06, leflynn wrote:
    Simple challenge to create a 26 word list where the starting and ending letters are the same, with one word for each letter of the alphabet. Your score is the total number of letters. If you skip a letter, your score for that letter is 7. Can you get
    under 100 without consulting a dictionary? Let's use the scrabble players' word list.
    I tried.

    I failed with j, q, u (no, I don't count Ubuntu!), v, and
    x, z. That's 42 penalty points right there. Under 100 is 99 max, less 42
    is 57.

    Use A, I, and O as one-letter words, which means there are 17 words left
    to get with 54 letters. Burn 34 for firsts and lasts, leaving 20 letters
    / 17 words. So we need fourteen three-letter words:

    bob did eye gig huh mum nun pip tat wow

    covers b d e g h m n p t w (and in my view 'gig', 'huh', 'mum' and 'wow'
    are dodgy to say the least),

    leaving these seven:

    c f k l o r s

    We'd have to find three-letter words for four of them and four-letter
    words for the remainder. I don't see it.

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

    Good try without resorting to looking up to see what obscure words are in the Scrabble list.
    (It has three-letter words for "u" and "v" and five-letter words for "x" and "q".)
    I don't see your "y" word and you are trying to get "o" twice.
    Your four "dodgy" words look fine to me.
    In another recent rec.puzzles thread, "mm" and "zzz" were proposed as solving words for a different challenge.
    They would certainly help here.
    L. Flynn

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  • From Richard Heathfield@21:1/5 to leflynn on Mon Oct 18 22:00:51 2021
    On 18/10/2021 21:50, leflynn wrote:
    you are trying to get "o" twice

    Oopo!

    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within

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    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From leflynn@21:1/5 to leflynn on Mon Oct 25 10:43:21 2021
    On Monday, October 18, 2021 at 1:06:19 PM UTC-4, leflynn wrote:
    Simple challenge to create a 26 word list where the starting and ending letters are the same, with one word for each letter of the alphabet. Your score is the total number of letters. If you skip a letter, your score for that letter is 7. Can you get
    under 100 without consulting a dictionary? Let's use the scrabble players' word list.
    L. Flynn
    Here are three lists. The first is made entirely of non-trivial Palindromes (Score of 99). The second improves on it by including non-palindrome words of two or more letters (Score of 90). And the third allows words of a single letter (Score of 84). One-
    letter words are not in the Scrabble dictionary. Note Collins Scrabble Words has “oo” in it.
    AA 2 A
    BIB 5
    CIVIC 10 CHIC
    DAD 13
    EYE 16
    ------- 23 FIEF
    GIG 26
    HAH 29
    ------- 36 INTI I
    ------- 43
    KOOK 47
    LEVEL 52 LULL
    MM 54
    NUN 57
    OHO 60 O
    POP 63
    QAJAQ 68
    RADAR 73 ROAR
    SIS 76
    TAT 79
    ULU 82
    VAV 85
    WOW 88
    XEROX 93
    YAY 96
    ZZZ 99 90 84

    Ob. Puzzle. Similar list to the first but the goal is to find the longest palindrome words for each letter.

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