• #### Word arithmetic : (CARL * R) + GINNOW = COINER

From James Dow Allen@21:1/5 to Carl G. on Sun Jun 28 02:17:21 2020
Recently, champion puzzler Carl G. posted a cryptic message in rec.puzzles:
testit.

Dammit, I'm a coder not a mind-reader! What are you testing?

Given that
(a) Carl frequently posted word problems,
(b) He is an excellent COINER of all sorts of puzzles, and
(c) His surname might be Ginnow
... I'm going to guess that he's testing whether rec.puzzles
is still capable of designing word arithmetic puzzles, with
unique solutions. I think we are:

(CARL * R) + GINNOW = COINER

Since Carl may be trying to ATTRACT interest in rec.p,
I'll submit another, which may be rather easy.
(CARL * R) + GINNOW = ATTRACT

I hope others also post word arithmetic puzzles -- I'd like
to show off my own! :-)

But again, I'm not a mind-reader. Perhaps Carl is annoyed
that nobody has responded to some of his puzzles,
e.g. "Resistance is Futile":

On Monday, July 10, 2000 at 2:00:00 PM UTC+7, Carl G. wrote:
You have a set of ten very precise resistors (assume that they have an exact resistance value). The resistors can be used individually, in parallel, or in series. The resistance of two resistors in series is given by the sum of the two resistances ( = r1+r2). The resistance of two resistors in parallel is given by the reciprocal of the sum of the reciprocals of the two resistances (= 1 / (1/r1 + 1/r2)). Find the set of ten resistors that forms the largest contiguous range of integral resistances, starting at 1 (in ohms)?

For example: The set of ten resistors: 1, 2, 4, 8, 16, 32, 64, 128, 256,
and 512 ohms, could form all of the resistances from 1 to 1023 by only using them in series (just convert the desired resistance value into binary and
use the resistors that correspond to each non-zero bit). Can you get a larger range by also using your set in parallel?

Can you find a larger contiguous range of integral resistances if you don't have to start at 1 ohm?

Carl G.

"Doing things in series may have serious consequences, but doing things in parallel may have perilous consequences." - C. Ginnow

My excuse is that I was AWOL from rec,puzzles in 2000.
I'll to look into this puzzle tomorrow.

James Dow Allen

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• From Edward Murphy@21:1/5 to James Dow Allen on Sun Jun 28 10:08:27 2020
On 6/28/2020 2:17 AM, James Dow Allen wrote:

Recently, champion puzzler Carl G. posted a cryptic message in rec.puzzles:
testit.

Dammit, I'm a coder not a mind-reader! What are you testing?

Given that
(a) Carl frequently posted word problems,
(b) He is an excellent COINER of all sorts of puzzles, and
(c) His surname might be Ginnow
... I'm going to guess that he's testing whether rec.puzzles
is still capable of designing word arithmetic puzzles, with
unique solutions. I think we are:

(CARL * R) + GINNOW = COINER

Partial solution:

This includes all ten digits (ACEGILNORW).

CARL * R <= 9999 * 9 = 89991, so:
C = G + 1
O < I
E > O

Also, if CARL * R <= 9999, then I < N, but also I = 9 and O = 0 (contradiction). So R > 1.

(L * R) + W = R mod 10
(L * R) = R - W (non-zero) mod 10
so L != 0, R != 0, and we can also rule out
(L = 2, R = 5)
and
(L = 5, R = 2)

Since Carl may be trying to ATTRACT interest in rec.p,
I'll submit another, which may be rather easy.
(CARL * R) + GINNOW = ATTRACT

Partial solution:

This includes all ten digits (ACGILNORTW).

Again, CARL * R is at most 5 digits, so:

?????
+ GINNOW
-------
ATTRACT

so A = 1, G = 9, T = 0.

CARL * R must be five digits, otherwise we would also get I = 9.

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• From Ilan Mayer@21:1/5 to James Dow Allen on Sun Jun 28 10:39:49 2020
On Sunday, 28 June 2020 05:17:23 UTC-4, James Dow Allen wrote:
Recently, champion puzzler Carl G. posted a cryptic message in rec.puzzles: >> testit.

Dammit, I'm a coder not a mind-reader! What are you testing?

Given that
(a) Carl frequently posted word problems,
(b) He is an excellent COINER of all sorts of puzzles, and
(c) His surname might be Ginnow
... I'm going to guess that he's testing whether rec.puzzles
is still capable of designing word arithmetic puzzles, with
unique solutions. I think we are:

(CARL * R) + GINNOW = COINER

Since Carl may be trying to ATTRACT interest in rec.p,
I'll submit another, which may be rather easy.
(CARL * R) + GINNOW = ATTRACT

I hope others also post word arithmetic puzzles -- I'd like
to show off my own! :-)

But again, I'm not a mind-reader. Perhaps Carl is annoyed
that nobody has responded to some of his puzzles,
e.g. "Resistance is Futile":

On Monday, July 10, 2000 at 2:00:00 PM UTC+7, Carl G. wrote:
You have a set of ten very precise resistors (assume that they have an exact
resistance value). The resistors can be used individually, in parallel, or in series. The resistance of two resistors in series is given by the sum of
the two resistances ( = r1+r2). The resistance of two resistors in parallel
is given by the reciprocal of the sum of the reciprocals of the two resistances (= 1 / (1/r1 + 1/r2)). Find the set of ten resistors that forms
the largest contiguous range of integral resistances, starting at 1 (in ohms)?

For example: The set of ten resistors: 1, 2, 4, 8, 16, 32, 64, 128, 256, and 512 ohms, could form all of the resistances from 1 to 1023 by only using
them in series (just convert the desired resistance value into binary and use the resistors that correspond to each non-zero bit). Can you get a larger range by also using your set in parallel?

Can you find a larger contiguous range of integral resistances if you don't have to start at 1 ohm?

Carl G.

"Doing things in series may have serious consequences, but doing things in parallel may have perilous consequences." - C. Ginnow

My excuse is that I was AWOL from rec,puzzles in 2000.
I'll to look into this puzzle tomorrow.

James Dow Allen

SPOILER
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( CARL * R ) + GINNOW = COINER -> ( 7891 * 9 ) + 654420 = 725439
( CARL * R ) + GINNOW = ATTRACT -> ( 5136 * 3 ) + 987742 = 1003150

__/\__
\ /
__/\\ //\__ Ilan Mayer
\ /
/__ __\
||

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• From James Dow Allen@21:1/5 to Ilan Mayer on Sun Jun 28 12:38:11 2020
On Monday, June 29, 2020 at 12:39:51 AM UTC+7, Ilan Mayer wrote:
On Sunday, 28 June 2020 05:17:23 UTC-4, James Dow Allen wrote:
Recently, champion puzzler Carl G. posted a cryptic message in rec.puzzles: >> testit.
[et cetera]

( CARL * R ) + GINNOW = COINER -> ( 7891 * 9 ) + 654420 = 725439
( CARL * R ) + GINNOW = ATTRACT -> ( 5136 * 3 ) + 987742 = 1003150

ILAN x MAYER = EXEMPLAR

BRAINY + ILAN + MAYER = MARVEL

James

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• From James Dow Allen@21:1/5 to James Dow Allen on Mon Jun 29 07:53:48 2020
On Monday, June 29, 2020 at 2:38:13 AM UTC+7, James Dow Allen wrote:
On Monday, June 29, 2020 at 12:39:51 AM UTC+7, Ilan Mayer wrote:
On Sunday, 28 June 2020 05:17:23 UTC-4, James Dow Allen wrote:
Recently, champion puzzler Carl G. posted a cryptic message in rec.puzzles:
testit.
[et cetera]

( CARL * R ) + GINNOW = COINER -> ( 7891 * 9 ) + 654420 = 725439
( CARL * R ) + GINNOW = ATTRACT -> ( 5136 * 3 ) + 987742 = 1003150

ILAN x MAYER = EXEMPLAR

BRAINY + ILAN + MAYER = MARVEL

I'm disappointed nobody but Edward Murphy and Ilan Mayer
have joined in the fun. But I won't give up yet.
Now is the season for campaign mottoes. Wouldn't it add to
the fun if such mottoes had to be valid base-10 word arithmetic
puzzles with unique solutions? Here's one for the incumbent:

MAKE x AMERIKA = INEPT x AGAIN

It will be easier to make a motto for the Blue-shirts when we
know who their V.P. nominee will be. Here are two possibilities:

PRAISE = BIDEN + HARRIS

BIDEN + BALDWIN = LOVABLE

James Dow Allen

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• From Richard Heathfield@21:1/5 to James Dow Allen on Tue Jun 30 01:45:28 2020
On 29/06/2020 15:53, James Dow Allen wrote:

<snip>

Now is the season for campaign mottoes. Wouldn't it add to
the fun if such mottoes had to be valid base-10 word arithmetic
puzzles with unique solutions? Here's one for the incumbent:

MAKE x AMERIKA = INEPT x AGAIN

Either you screwed up or I did. Probably me. I can find no valid
solutions. (I even brute-forced it to check.)

--
Richard Heathfield
Email: rjh at cpax dot org dot uk
"Usenet is a strange place" - dmr 29 July 1999
Sig line 4 vacant - apply within

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• From James Dow Allen@21:1/5 to Richard Heathfield on Mon Jun 29 21:48:42 2020
On Tuesday, June 30, 2020 at 7:45:34 AM UTC+7, Richard Heathfield wrote:
On 29/06/2020 15:53, James Dow Allen wrote:

MAKE x AMERIKA = INEPT x AGAIN

Either you screwed up or I did. Probably me. I can find no valid
solutions. (I even brute-forced it to check.)

I screwed up, not you. :-( :-(
My face is so red that I'd better crawl into a corner and pout.

Back in the day, I had the humility and diligence to check
my results, as well as the acuity to not actually need the checking.
(Maybe Viagra would have helped?)

Mea culpa. Sorry for the time-wasting.

I don't blame any of you for never trusting me again, but this
useless one I did double-check:
MAKE x AMERIKA = MANTIS x AGAIN

In a vain effort to make amends, I offer this:
Richard -- what is your middle name? If it is 'Dan'
then this works in Base-12:
RICHARD * DAN = HEATHFIELD

Or would you like to change your middle name to 'Veil'?
I think this works in Base-11:
RICHARD * VEIL = HEATHFIELD

Yes, I am double-checking these now. :-(
I think there are some nifty middle-names for
you in Base-13 if you want to go that far! :-)

James

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• From Carl G.@21:1/5 to James Dow Allen on Thu Jul 2 13:59:03 2020
On 6/28/2020 2:17 AM, James Dow Allen wrote:
Recently, champion puzzler Carl G. posted a cryptic message in rec.puzzles:
testit.

Dammit, I'm a coder not a mind-reader! What are you testing?

Given that
(a) Carl frequently posted word problems,
(b) He is an excellent COINER of all sorts of puzzles, and
(c) His surname might be Ginnow
... I'm going to guess that he's testing whether rec.puzzles
is still capable of designing word arithmetic puzzles, with
unique solutions. I think we are:

(CARL * R) + GINNOW = COINER

Since Carl may be trying to ATTRACT interest in rec.p,
I'll submit another, which may be rather easy.
(CARL * R) + GINNOW = ATTRACT

I hope others also post word arithmetic puzzles -- I'd like
to show off my own! :-)

But again, I'm not a mind-reader. Perhaps Carl is annoyed
that nobody has responded to some of his puzzles,
e.g. "Resistance is Futile":

...

My excuse is that I was AWOL from rec,puzzles in 2000.
I'll to look into this puzzle tomorrow.

James Dow Allen

I was installing Mozilla Thunderbird on an old laptop computer and
accidentally sent a test message when in my news account, rather than my default account.

OBPuzzle: Anagram/alphametic below:

CARL+GINNOW = A*CLOWN+GRIN

--
Carl G.
--
Carl G.

--
This email has been checked for viruses by AVG.
https://www.avg.com

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• From Richard Heathfield@21:1/5 to Carl G. on Fri Jul 3 00:46:29 2020
On 02/07/2020 21:59, Carl G. wrote:
On 6/28/2020 2:17 AM, James Dow Allen wrote:
Recently, champion puzzler Carl G. posted a cryptic message in
rec.puzzles:
testit.

Dammit, I'm a coder not a mind-reader!  What are you testing?

Given that
(a) Carl frequently posted word problems,
(b) He is an excellent COINER of all sorts of puzzles, and
(c) His surname might be Ginnow
... I'm going to guess that he's testing whether rec.puzzles
is still capable of designing word arithmetic puzzles, with
unique solutions.  I think we are:

(CARL * R) + GINNOW = COINER

Since Carl may be trying to ATTRACT interest in rec.p,
I'll submit another, which may be rather easy.
(CARL * R) + GINNOW = ATTRACT

I hope others also post word arithmetic puzzles -- I'd like
to show off my own!  :-)

But again, I'm not a mind-reader.  Perhaps Carl is annoyed
that nobody has responded to some of his puzzles,
e.g. "Resistance is Futile":

...

My excuse is that I was AWOL from rec,puzzles in 2000.
I'll to look into this puzzle tomorrow.

James Dow Allen

I was installing Mozilla Thunderbird on an old laptop computer and accidentally sent a test message when in my news account, rather than my default account.

OBPuzzle: Anagram/alphametic below:

CARL+GINNOW = A*CLOWN+GRIN

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0

CARL+GINNOW = A*CLOWN+GRIN

8274 + 163395 = 2 * 84953 + 1763

--
Richard Heathfield
Email: rjh at cpax dot org dot uk
"Usenet is a strange place" - dmr 29 July 1999
Sig line 4 vacant - apply within

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