I'm trying to enhance the robustness of `install/install_utils` script
in quantum espresso package, with the following make file script as
described here[1]:

```

# Copyright (C) 2001-2016 Quantum ESPRESSO group
#
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; either version 2
# of the License. See the file `License' in the root directory
# of the present distribution.
#
# Utilities

###########################################################
# Template function
# $(1) = package name
# $(2) = package URL
# $(3) = directory name
# $(4) = plugin/code name ###########################################################

define download_and_unpack
@(if ! gzip -t ../archive/`echo "$(2)" | sed 's/.*\///;s/.*=//'` >
/dev/null 2>&1 ; then \
rm -fr ../archive/`echo "$(2)" | sed 's/.*\///;s/.*=//'`; \
rm -fr ../$(3); \
wget -O ../archive/`echo "$(2)" | sed 's/.*\///;s/.*=//'` $(2) >
/dev/null 2>&1; \
if test "`echo $$?`" -ne "0" ; then \
curl -o ../archive/`echo "$(2)" | sed 's/.*\///;s/.*=//'` $(2) >
/dev/null 2>&1; \
if test "`echo $$?`" -ne "0" ; then \
echo "*** Unable to download $(4). Test whether curl or wget is
installed and working," ; \
echo "*** if you have direct access to internet. If not, copy into
archive/ the file" ; \
echo "*** located here $(2)" ; \
exit 1 ; fi ; fi ; fi)
if test $? -eq 0 -a ! -e ../$(3); then \
(gzip -dc ../archive/`echo "$(2)" | sed 's/.*\///;s/.*=//'` | \
(cd ../ ; tar -xvf - ) ) ; \
if test "`echo $$?`" -ne "0" ; then \
echo "*** Unable to download $(2)." ; \
echo "*** Verify that the url is correct." ; \
exit 1 ; \
else \
(cd ../ ; ln -s $(1) $(3)) ; fi ; fi
endef
```

But it seems that the `$?' used above can't obtain the exit status of
the code block in @(...) when used from outside the @() structure [2].
So, I want to know if I can reliably obtain the exit status of the
code block in @(...) from outside the @() structure. Any hints will be
greatly appreciated. Also see here [3] for relevant discussion.

[1] https://gitlab.com/QEF/q-e/-/issues/435
[2] https://gitlab.com/QEF/q-e/-/merge_requests/1713#note_812794803
[3] https://lists.gnu.org/archive/html/help-make/2022-01/msg00016.html

Regards,
HZ

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On 18.01.2022 08:30, hongy...@gmail.com wrote:

I'm trying to enhance the robustness of [...]

This is a joke, isn't it?

[ shell-like but actually non-shell code deleted ]

Please make clear in the subject line if you refer in your post to
specific tools with non-shell syntax and name the respective tool.
(If possible post in a tool-specific forum.)

BTW, isn't it possible to create a shell script for all that shell
stuff instead of twisting the shell code to fit into that tool?

Janis

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On Tuesday, January 18, 2022 at 4:32:38 PM UTC+8, Janis Papanagnou wrote:

On 18.01.2022 08:30, hongy...@gmail.com wrote:

I'm trying to enhance the robustness of [...]

This is a joke, isn't it?

This is a serious question I don't understand. Why do you say that?

[ shell-like but actually non-shell code deleted ]

Please make clear in the subject line if you refer in your post to
specific tools with non-shell syntax and name the respective tool.
(If possible post in a tool-specific forum.)

BTW, isn't it possible to create a shell script for all that shell
stuff instead of twisting the shell code to fit into that tool?

It's called by gnu make command, and I also don't know why the original author of this script wrote it so obscurely.

--- SoupGate-Win32 v1.05
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On 2022-01-18 02:30, hongy...@gmail.com wrote:

I'm trying to enhance the robustness of `install/install_utils` script
in quantum espresso package, with the following make file script as
described here[1]:

As the other poster alluded to, this is NOT a shell question. It is a
question about Makefile syntax. You are asking if the exit status of
shell code inside a Makefile can be accessed elsewhere in the Makefile.
In other words, completely outside the shell. So that makes it a
question for Makefile experts (maybe there is a mailing list for that)
rather than the shell experts in this newsgroup.

It is also easily answered by reading the documentation for (GNU) make
or a quick Google search. Both are things you should do before posting
here or anywhere else.

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On Wednesday, January 19, 2022 at 3:49:52 AM UTC+8, John-Paul Stewart wrote:

On 2022-01-18 02:30, hongy...@gmail.com wrote:

I'm trying to enhance the robustness of `install/install_utils` script
in quantum espresso package, with the following make file script as described here[1]:

As the other poster alluded to, this is NOT a shell question. It is a question about Makefile syntax. You are asking if the exit status of
shell code inside a Makefile can be accessed elsewhere in the Makefile.
In other words, completely outside the shell. So that makes it a
question for Makefile experts (maybe there is a mailing list for that)
rather than the shell experts in this newsgroup.

It is also easily answered by reading the documentation for (GNU) make
or a quick Google search. Both are things you should do before posting
here or anywhere else.

Thank you very much, I found the following example here [1]:

=== begin ===
To those who can't still fix it, the original snippet in the question missed a semicolon after mycommand. So, the working example is:

mycommand; \ # <<== here's the missing semicolon
if [ $$? -ne 0 ]; \
then \
echo "mycommand failed"; \
false; \
fi
=== end ===

[1] https://stackoverflow.com/a/70105815

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On 2022-01-18 21:23, hongy...@gmail.com wrote:

Thank you very much, I found the following example

Which has nothing to do with your specific question. Adding semicolons
will not help you obtain a shell's exit status in a Makefile. You
missed the relevant info on the page you cited AND you missed the point
in my previous post (and Janis' post) that this is not the place to
discuss Makefile syntax.

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On Thursday, January 20, 2022 at 7:53:11 AM UTC+8, John-Paul Stewart wrote:

On 2022-01-18 21:23, hongy...@gmail.com wrote:

Thank you very much, I found the following example

Which has nothing to do with your specific question. Adding semicolons
will not help you obtain a shell's exit status in a Makefile. You
missed the relevant info on the page you cited AND you missed the point
in my previous post (and Janis' post) that this is not the place to
discuss Makefile syntax.

Anyway, I've figured out the problem based on the comments given by Paul Smith here [1].

[1] https://lists.gnu.org/archive/html/help-make/2022-01/msg00019.html

HZ

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