Count how many zeros are at the end of your int:

def end_zeros(num):
s = str(num)
return len(s) - len(s.rstrip("0"))


print(end_zeros(10)) # == 1
print(end_zeros(101)) # == 0
print(end_zeros(245)) # == 0
print(end_zeros(100100)) # == 2


---------------- Writing a loop (using % and // ) feels like [reinventing the wheel] and seems intrinsically wrong.


i like this code (above) because it's not reinventing the wheel --- the Python implementor has already done the loop (using % and // ), so i'm just using that efficient tool (routine).

--- SoupGate-Win32 v1.05
* Origin: fsxNet Usenet Gateway (21:1/5)