On 8/21/22, simone zambonardi <
simone.zambonardi@gmail.com> wrote:
Hi, I am running a program with the punishment subrocess.Popen(...) what I should do is to stop the script until the launched program is fully open.
How can I do this? I used a time.sleep() function but I think there are
other ways. Thanks
In Windows, WaitForInputIdle() waits until a thread in a process
creates one or more windows and its message loop goes idle. Usually
this is the main UI thread. Console processes are not supported.
For example:
import ctypes
import subprocess
user32 = ctypes.WinDLL('user32', use_last_error=True)
INFINITE = 0xFFFF_FFFF
WAIT_FAILED = 0xFFFF_FFFF
WAIT_TIMEOUT = 0x0000_0102
# Waiting on a console process fails with ERROR_NOT_GUI_PROCESS.
# This case be handled in other ways, depending on the need. ERROR_NOT_GUI_PROCESS = 1471
user32.WaitForInputIdle.restype = ctypes.c_ulong user32.WaitForInputIdle.argtypes = (ctypes.c_void_p, ctypes.c_ulong)
def wait_for_input_idle(proc, timeout=None):
if isinstance(proc, subprocess.Popen):
handle = int(proc._handle)
args = p.args
else:
handle = int(proc)
args = ''
if timeout is None:
timeout_ms = INFINITE
elif timeout < 0:
raise ValueError('timeout cannot be negative')
else:
timeout_ms = int(timeout * 1000)
if timeout_ms >= INFINITE:
raise OverflowError('timeout is too large')
status = user32.WaitForInputIdle(handle, timeout_ms)
if status == WAIT_FAILED:
raise ctypes.WinError(ctypes.get_last_error())
elif status == WAIT_TIMEOUT:
raise subprocess.TimeoutExpired(args, timeout)
assert status == 0
return
if __name__ == '__main__':
import time
t0 = time.time()
p = subprocess.Popen(['pythonw.exe', '-m', 'idlelib'])
try:
wait_for_input_idle(p, 5)
except:
p.terminate()
raise
wait_time = time.time() - t0
print(f'wait time: {wait_time:.3f} seconds')
try:
p.wait(5)
except subprocess.TimeoutExpired:
p.terminate()
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