I have a milling setup on my lathe. (Emco Maximat VP10)
The motor spins at 1380 rpm.
The spindle speeds are 350 640 780 and 1450.
Derive a possible (probable) configuration of gears with
their tooth count.
Hints:
do not expect gears with more than say 30 teeth
[This is an approximate problem, if you had to calculate gears
for thread cutting at the lathe, ratio's are fixed. ]
On Wednesday, January 4, 2023 at 4:01:33 AM UTC-5, none albert wrote:
I have a milling setup on my lathe. (Emco Maximat VP10)
The motor spins at 1380 rpm.
The spindle speeds are 350 640 780 and 1450.
Derive a possible (probable) configuration of gears with
their tooth count.
Hints:
do not expect gears with more than say 30 teeth
[This is an approximate problem, if you had to calculate gears
for thread cutting at the lathe, ratio's are fixed. ]
Not sure what you meany by "an approximate problem".
Are you saying you only need to be close?
The motor speed is 1380 RPM. The first spindle speed is 350. Eliminating the common divisors yields these divisors, where each number is 30 or less.
1380 - 6 and 23
350 - 5 and 7
So to keep the number of teeth below 30 in all cases, requires two sets of gears with ratios of 5:6 and 7:23.
1380 - 3 and 23
640 - 4 and 8
So 4:3 and 8:23
1380 - 23
780 - 13
So 13:23
1380 - 6 and 23
1450 - 5 and 29
So 5:6 and 29:23
With an algorithm for finding appropriate divisors, this could be automated. However, it's not a time intensive process to do it by hand. I think this took me 5 minutes, most of which was
formatting the data from the web page to calculate the divisors.
--
Rick C.
I have a milling setup on my lathe. (Emco Maximat VP10)
The motor spins at 1380 rpm.
The spindle speeds are 350 640 780 and 1450.
Derive a possible (probable) configuration of gears with
their tooth count.
Hints:
do not expect gears with more than say 30 teeth
[This is an approximate problem, if you had to calculate gears
for thread cutting at the lathe, ratio's are fixed. ]
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