How do I get the MAX (or another aggregate function) for of a column of each row, OVER its preceding 3 days worth of rows?

SQL example with expected output and db schema: http://sqlfiddle.com/#!17/24686/3

Thanks for all suggestions

PS: Also interested with how I can cover 3 work days rather than calendar days

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On 08/13/2017 01:48 PM, Alec Taylor wrote:

How do I get the MAX (or another aggregate function) for of a column of each row, OVER its preceding 3 days worth of rows?

SQL example with expected output and db schema: http://sqlfiddle.com/#!17/24686/3

Thanks for all suggestions

PS: Also interested with how I can cover 3 work days rather than calendar days

Sketch:

MAX(x) OVER (PARTITION by ...
ORDER BY ...
RANGE BETWEEN CURRENT ROW AND 3 PRECEDING)

The groups I monitor on usenet have zero to none activity. I suggest you
post your question on http://stackoverflow.com

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On 14.08.2017 14:28, Lennart Jonsson wrote:

On 08/13/2017 01:48 PM, Alec Taylor wrote:

How do I get the MAX (or another aggregate function) for of a column
of each row, OVER its preceding 3 days worth of rows?

SQL example with expected output and db schema:
http://sqlfiddle.com/#!17/24686/3

Thanks for all suggestions

PS: Also interested with how I can cover 3 work days rather than
calendar days

Sketch:

MAX(x) OVER (PARTITION by ...
ORDER BY ...
RANGE BETWEEN CURRENT ROW AND 3 PRECEDING)

If I am not mistaken this requires that data is rolled up to days
already. Could be achieved with a WITH clause though.

The nice thing is this works easier with the three work days as you
would just have to filter out weekends. That would still miss public
holidays which would require a bit more.

The groups I monitor on usenet have zero to none activity. I suggest you
post your question on http://stackoverflow.com

Some old fashioned guys are still around. :-)

Cheers

robert

--
remember.guy do |as, often| as.you_can - without end http://blog.rubybestpractices.com/

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On 08/14/2017 08:20 PM, Robert Klemme wrote:
[...]

MAX(x) OVER (PARTITION by ...
ORDER BY ...
RANGE BETWEEN CURRENT ROW AND 3 PRECEDING)

If I am not mistaken this requires that data is rolled up to days
already. Could be achieved with a WITH clause though.

You can do this in the window:

MAX(x) OVER (PARTITION by ...
ORDER BY date(...)
RANGE BETWEEN CURRENT ROW AND 3 PRECEDING)

Some DBMS does only support range over numbers, a trick is to map the
date to a number with for example a JULIAN_DAY function:

MAX(x) OVER (PARTITION by ...
ORDER BY JULIAN_DAY(...)
RANGE BETWEEN CURRENT ROW AND 3 PRECEDING)

The nice thing is this works easier with the three work days as you
would just have to filter out weekends. That would still miss public holidays which would require a bit more.

I agree, a calendar table is often very usefull

The groups I monitor on usenet have zero to none activity. I suggest you
post your question on http://stackoverflow.com

Some old fashioned guys are still around. :-)

:-)


/Lennart

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