• Question regarding an elevator

    From vallor@21:1/5 to All on Fri Jun 30 19:08:03 2023
    [ This is a repost of the following article: ]
    [ From: vallor <vallor@cultnix.org> ]
    [ Subject: Question regarding an elevator ]
    [ Newsgroups: sci.physics ]
    [ Message-ID: <u7n7da$2jpl7$1@dont-email.me> ]

    Thought experiment:

    Einstein's elevator.

    In an elevator sitting on the ground on Earth, gravity would be measured
    as higher near the floor than the ceiling, given sufficiently sensitive equipment. (1/d^2)

    Accelerating the elevator at 1G, there won't be the difference in "gravity" from
    the ceiling to the floor.

    What does that mean with regards to "locality"? Is that just a measure of
    how sensitive the instruments you're carrying are? Or...?

    (I am but an egg.)

    --
    -v

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  • From Sn!pe@21:1/5 to vallor on Fri Jun 30 20:55:33 2023
    vallor <vallor@vallor.earth> wrote:

    (I am but an egg.)

    Which of us came first?

    Can the chatbot can answer that?
    Maybe the gravitational question too?

    --
    ^Ï^. – Sn!pe – <https://youtu.be/_kqytf31a8E>

    My pet rock Gordon just is.

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  • From vallor@21:1/5 to mitchr...@gmail.com on Fri Jun 30 19:41:39 2023
    XPost: sci.physics

    On Fri, 30 Jun 2023 12:29:05 -0700 (PDT), mitchr...@gmail.com wrote:

    On Friday, June 30, 2023 at 11:37:37 AM UTC-7, vallor wrote:
    Thought experiment:

    Einstein's elevator.

    In an elevator sitting on the ground on Earth, gravity would be measured
    as higher near the floor than the ceiling, given sufficiently sensitive
    equipment. (1/d^2)

    The strength of gravity is equal in contractile curvature.
    There is no inner gravity drop off. Feynman was a problem
    where he replaced original GR by inner drop off.
    At a BH how can there be Feynman's inner drop off gravity?
    He said it would go to zero. So how could gravity in a BH
    do it?


    Accelerating the elevator at 1G, there won't be the difference in "gravity" from
    the ceiling to the floor.

    Accelerating is increased speed it is not the force of gravity.
    Motion is like force. It can get weight.

    Thank you for the response, very much appreciated.

    I was referring to the observation that Einstein made that one
    couldn't tell the difference from within an elevator in either
    situation. I was pointing out that with sensitive enough instruments,
    you can tell the difference. The gedanken-experiment might
    not hold up:

    Perhaps the concept of "locality" might have something
    to do with "how sensitive are your instruments"... What do you think?

    Thanks,

    -Scott

    cc: comp.ai.shells, where the discussion first began
    fu2: sci.physics


    Mitchell Raemsch

    What does that mean with regards to "locality"? Is that just a measure of
    how sensitive the instruments you're carrying are? Or...?

    (I am but an egg.)

    --
    -v

    --- SoupGate-Win32 v1.05
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  • From vallor@21:1/5 to vallor on Fri Jun 30 20:49:19 2023
    On Fri, 30 Jun 2023 19:08:03 GMT, vallor wrote:

    [ This is a repost of the following article:
    ]
    [ From: vallor <vallor@cultnix.org>
    ]
    [ Subject: Question regarding an elevator
    ]
    [ Newsgroups: sci.physics
    ]
    [ Message-ID: <u7n7da$2jpl7$1@dont-email.me>
    ]

    Thought experiment:

    Einstein's elevator.

    In an elevator sitting on the ground on Earth, gravity would be measured
    as higher near the floor than the ceiling, given sufficiently sensitive equipment. (1/d^2)

    Accelerating the elevator at 1G, there won't be the difference in
    "gravity" from the ceiling to the floor.

    What does that mean with regards to "locality"? Is that just a measure
    of how sensitive the instruments you're carrying are? Or...?

    (I am but an egg.)

    User
    Thought experiment:

    Einstein's elevator. (Special relativity)

    In an elevator sitting on the ground on Earth, gravity would be measured
    as higher near the floor than the ceiling, given sufficiently sensitive equipment. (1/d^2)

    Accelerating the elevator at 1G, there won't be the difference in
    "gravity" from
    the ceiling to the floor.

    Wondering if that matters to Special Relativity, or if it
    was just a broader gedanken experiment? Or...?

    Thank you for any insights you have on this. :)
    ChatGPT
    Einstein's "Elevator" thought experiment is a staple in our understanding
    of General Relativity (GR), not Special Relativity (SR). SR deals with
    inertial frames of reference, which means frames that are either at rest
    or moving at constant velocity. It does not account for the effects of
    gravity or acceleration, and therefore doesn't directly concern itself
    with the hypothetical elevator scenario.

    When Einstein came up with his elevator thought experiment, he was trying
    to demonstrate a fundamental idea of General Relativity, which is the
    principle of equivalence. This principle essentially states that the
    effects of gravity and acceleration are locally indistinguishable. In
    other words, if you were in a closed elevator, you wouldn't be able to
    tell if you were being pulled downward by gravity on Earth, or if the
    elevator was being accelerated upward through space at a rate of 9.8 m/
    s^2.

    Now, to your question regarding the variation of gravity in an elevator
    resting on Earth (where gravity is stronger at the floor than at the
    ceiling due to the inverse square law) versus in an accelerating elevator
    in space (where the "gravity" feels uniform). While this difference exists
    and is indeed measurable with very sensitive equipment, it does not fundamentally challenge or change the principle of equivalence, because
    the principle is a local concept.

    What do we mean by "local"? If the elevator is small enough (so that
    variations in gravitational field strength across its size are
    negligible), then there's no experiment you could conduct inside the
    elevator to determine whether it's stationary in a gravitational field or
    in free space being accelerated. That's the essence of the equivalence principle.

    However, if the elevator is large enough that these variations in
    gravitational field strength are not negligible, then we'd say that the "locality" condition isn't satisfied. For example, you could imagine a
    scenario where the elevator is the size of a planet. Clearly, there would
    be a noticeable difference in gravity between the floor and the ceiling.
    But in this case, the equivalence principle isn't meant to apply, because
    the situation is no longer local.

    So, in short, while the variation in gravitational strength is an
    interesting point and certainly real, it doesn't undermine the validity of
    the equivalence principle because this principle is only meant to apply to small, local regions of spacetime. For larger regions where the variation
    in gravitational strength becomes noticeable, one would need to apply the
    full machinery of General Relativity.

    _ _ _ _ _

    --
    -v

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  • From Sn!pe@21:1/5 to vallor on Fri Jun 30 22:35:41 2023
    [comp.ai.shells only]

    vallor <vallor@cultnix.org> wrote:
    [...]
    Perhaps the concept of "locality" might have something
    to do with "how sensitive are your instruments"... What do you think?

    Thanks,

    -Scott

    cc: comp.ai.shells, where the discussion first began
    fu2: sci.physics


    I don't read sp so I will take no further part in this discussion.

    --
    ^Ï^. – Sn!pe – <https://youtu.be/_kqytf31a8E>

    My pet rock Gordon just is.

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  • From Sn!pe@21:1/5 to vallor on Fri Jun 30 22:39:10 2023
    vallor <vallor@vallor.earth> wrote:

    [ This is a repost of the following article: ] [ From: vallor <vallor@cultnix.org> ] [ Subject: Question regarding an elevator ] [ Newsgroups: sci.physics ] [ Message-ID: <u7n7da$2jpl7$1@dont-email.me> ]

    Thought experiment:

    Einstein's elevator.

    In an elevator sitting on the ground on Earth, gravity would be measured
    as higher near the floor than the ceiling, given sufficiently sensitive equipment. (1/d^2)

    Accelerating the elevator at 1G, there won't be the difference in
    "gravity" from the ceiling to the floor.

    What does that mean with regards to "locality"? Is that just a measure of how sensitive the instruments you're carrying are? Or...?

    [...]

    Lacking context, I have nothing to add.

    --
    ^Ï^. – Sn!pe – <https://youtu.be/_kqytf31a8E>

    My pet rock Gordon just is.

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    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From Stefan Ram@21:1/5 to vallor on Sat Jul 1 11:44:31 2023
    vallor <vallor@cultnix.org> writes:
    I was referring to the observation that Einstein made that one
    couldn't tell the difference from within an elevator in either
    situation. I was pointing out that with sensitive enough instruments,
    you can tell the difference.

    The gravitational potential at the bottom of the elevator is

    V( x )= -GM/x, where

    x is the distance from the center of the Earth to the bottom
    of the elevator,
    G is the gravitational constant, and
    M the mass of the Earth.

    At the top, it's

    V( x + h )= -GM/( x + h ), where

    h is the height of the elevator.

    So the difference is

    -GM/( x + h )-( -GM/x )= GMh/( x^2 + hx )~ GMh/x^2.

    This difference can be made as small as wanted by reducing the
    height of the elevator. We also should reduce the size of the
    floor as otherwise the direction of the force differs between
    different points of the floor. So, it seems to me that for such
    gedanken-experiments one uses elevators of infinitesimal size!

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  • From Stefan Ram@21:1/5 to Stefan Ram on Sat Jul 1 13:02:46 2023
    ram@zedat.fu-berlin.de (Stefan Ram) writes:
    So, it seems to me that for such
    gedanken-experiments one uses elevators of infinitesimal size!

    In cases where individuals reject the concept of an
    infinitely minute elevator size, it should be noted that for
    each measuring instrument's sensitivity level, there exists
    a finite maximum height beyond which the device becomes
    unable to detect changes within the elevator's interior.

    The traditional understanding of "infinitesimal" magnitude has
    since evolved within contemporary mathematical theory through the
    application of tangential functors, in which linear approximations
    have superseded conventional considerations of infinitesimal size.

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  • From vallor@21:1/5 to Stefan Ram on Sat Jul 1 13:59:33 2023
    On 1 Jul 2023 11:44:31 GMT, Stefan Ram wrote:

    vallor <vallor@cultnix.org> writes:
    I was referring to the observation that Einstein made that one couldn't >>tell the difference from within an elevator in either situation. I was >>pointing out that with sensitive enough instruments,
    you can tell the difference.

    The gravitational potential at the bottom of the elevator is

    V( x )= -GM/x, where

    x is the distance from the center of the Earth to the bottom
    of the elevator,
    G is the gravitational constant, and M the mass of the Earth.

    At the top, it's

    V( x + h )= -GM/( x + h ), where

    h is the height of the elevator.

    So the difference is

    -GM/( x + h )-( -GM/x )= GMh/( x^2 + hx )~ GMh/x^2.

    This difference can be made as small as wanted by reducing the height
    of the elevator. We also should reduce the size of the floor as
    otherwise the direction of the force differs between different points
    of the floor. So, it seems to me that for such gedanken-experiments
    one uses elevators of infinitesimal size!

    Thank you so much for doing the math. It's been a while.

    Also, it seems to me that for an elevator accelerating at 1G
    in free space, the "top" accelerometer will actually
    register _heavier_ than the "bottom" accelerometer, due to
    gravity from the mass of the elevator.

    --
    -v

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