This reminded me of Olcott
<https://xkcd.com/2566/>
André
On 2022-02-28 22:47:44 +0000, olcott said:
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
These two lines contradict each other,
so at least one of them is false,
possibly both.
Mikko
Mikko <mikko.levanto@iki.fi> writes:
On 2022-02-28 22:47:44 +0000, olcott said:
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
These two lines contradict each other,
so at least one of them is false,
possibly both.
PO makes a habit of omitting the key conditions under which each line applies. This has been pointed out so often that it must be
deliberate. The trouble is that the conditions are what shows PO to be
wrong so he's spent some time trying to find words for his own
conditions that make it sound a bit like he is still talking about a
halt decider. The conditions are
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ if H applied to ⟨Ĥ⟩ halts, and
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn if H applied to ⟨Ĥ⟩ does not halt.
olcott <NoOne@NoWhere.com> writes:
On 3/1/2022 6:02 AM, Ben Bacarisse wrote:
Mikko <mikko.levanto@iki.fi> writes:
On 2022-02-28 22:47:44 +0000, olcott said:PO makes a habit of omitting the key conditions under which each line
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
These two lines contradict each other,
so at least one of them is false,
possibly both.
applies. This has been pointed out so often that it must be
deliberate. The trouble is that the conditions are what shows PO to be
wrong so he's spent some time trying to find words for his own
conditions that make it sound a bit like he is still talking about a
halt decider. The conditions are
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ if H applied to ⟨Ĥ⟩ halts, and
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn if H applied to ⟨Ĥ⟩ does not halt.
Those are not the conditions.
Indeed they are not. I made a typo. You, however, cannot give the
correct ones because they show you to be wrong. Instead you must pile
on the verbiage:
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
if embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ determines that its simulation of ⟨Ĥ⟩ ⟨Ĥ⟩ will
halt without aborting the simulation of its input
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
if embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ determines that its simulation of ⟨Ĥ⟩ ⟨Ĥ⟩ will
NOT halt without aborting the simulation of its input
If these were same as those in Linz you would use the far simpler
conditions from Linz, but in actual fact you are re-defining what
halting means hoping that you won't be called out on it.
I'll call you out on it: you have not changed your stance since you made
the fatal mistake of being crystal clear:
Me: do you still assert that H(P,P) == false is the "correct" answer
even though P(P) halts?
You: Yes that is the correct answer even though P(P) halts.
Until to accept that this is simply wrong, everything you say on the
topic is just hot air.
olcott <polcott2@gmail.com> writes:
I explain your mistake about this in terms of Turing machine deciders:
On 2/28/2022 11:59 AM, olcott wrote:
Concise refutation of halting problem proofs V63 [ Linz Proof ][ Ben's
mistake ]
You can't even be bothered to learn how to cite a Usenet post (it's not hard).
But that suits me fine. You appear to want to talk forever, whereas all
I want to do is remind readers that you are not addressing the halting problem,
and that you have been 100% clear about this in the past:
Me: do you still assert that H(P,P) == false is the "correct" answer
even though P(P) halts?
You: Yes that is the correct answer even though P(P) halts.
olcott <NoOne@NoWhere.com> writes:
On 3/2/2022 11:07 AM, Ben Bacarisse wrote:
olcott <NoOne@NoWhere.com> writes:
Linz confuses himself my making the TM descriptions less than a clear
as possible.
Have you looked at Linz's actual proof yet? It's theorem 12.2, a page
further on from the one you seem to be obsessed by.
Like I said my only reply to you will be to keep repeating the key
points that you failed to address until you address them completely.
I can't parse that sentence but it contains no hint that you have looked
at Linz's proof yet.
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