• Concise refutation of halting problem proofs V43 [where people get stuc

    From olcott@21:1/5 to All on Fri Dec 31 10:27:26 2021
    XPost: comp.theory, sci.logic, sci.math

    Proving that embedded_H at Ĥ.qx correctly maps its inputs ⟨Ĥ⟩ ⟨Ĥ⟩ to Ĥ.qn on the basis of the behavior of the UTM simulation of these inputs.

    *My criterion measure with Ben's notational conventions*
    H.q0 wM w ⊢* H.qy iff UTM(wM, w) halts
    H.q0 wM w ⊢* H.qn iff UTM(wM, w) does not halt

    We know that H would correctly decide the halt status of its input on
    the basis of correctly deciding the halt status of the UTM simulation of
    its input.

    We know this because a UTM simulation of the Turing machine description
    is computationally equivalent to the direct execution of this same
    Turing machine.

    Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ iff UTM(⟨Ĥ⟩ ⟨Ĥ⟩) at Ĥ.qx halts.
    Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn iff UTM(⟨Ĥ⟩ ⟨Ĥ⟩) at Ĥ.qx does not halt.

    THIS IS WHERE PEOPLE GET STUCK
    THIS IS WHERE PEOPLE GET STUCK
    THIS IS WHERE PEOPLE GET STUCK

    The criterion measure of H applies recursively such that the UTM would
    simulate itself.

    The following is the UTM simulation of a single input pair:
    (a) copies its input ⟨Ĥ⟩ to ⟨Ĥ⟩
    (b) simulates ⟨Ĥ⟩ applied to ⟨Ĥ⟩ with the UTM

    We know that this means that when embedded_H computes the mapping from
    its input ⟨Ĥ⟩ ⟨Ĥ⟩ to Ĥ.qy or Ĥ.qn on the basis of the behavior of the
    UTM simulation of this input that its transition to Ĥ.qn is correct.

    https://www.liarparadox.org/Peter_Linz_HP_315-320.pdf

    Linz, Peter 1990. An Introduction to Formal Languages and Automata. Lexington/Toronto: D. C. Heath and Company. (315-320)

    --
    Copyright 2021 Pete Olcott

    Talent hits a target no one else can hit;
    Genius hits a target no one else can see.
    Arthur Schopenhauer

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