• Re: Question for Olcott [ summing up where we are ]

    From olcott@21:1/5 to Dennis Bush on Tue May 24 09:57:03 2022
    XPost: comp.theory, sci.logic, sci.math

    On 5/24/2022 9:47 AM, Dennis Bush wrote:
    On Tuesday, May 24, 2022 at 10:19:28 AM UTC-4, olcott wrote:
    On 5/24/2022 8:57 AM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 11:47:56 PM UTC-4, olcott wrote:
    On 5/23/2022 10:16 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 11:08:54 PM UTC-4, olcott wrote:
    On 5/23/2022 10:05 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 11:01:56 PM UTC-4, olcott wrote:
    On 5/23/2022 9:57 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 10:48:39 PM UTC-4, olcott wrote: >>>>>>>>>> On 5/23/2022 9:40 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 10:32:55 PM UTC-4, olcott wrote: >>>>>>>>>>>> On 5/23/2022 9:23 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 10:18:37 PM UTC-4, olcott wrote: >>>>>>>>>>>>>> On 5/23/2022 9:09 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 9:50:28 PM UTC-4, olcott wrote: >>>>>>>>>>>>>>>> On 5/23/2022 8:40 PM, Richard Damon wrote:
    On 5/23/22 9:34 PM, olcott wrote:
    On 5/23/2022 8:29 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 9:24:47 PM UTC-4, olcott wrote: >>>>>>>>>>>>>>>>>>>> On 5/23/2022 8:15 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 9:08:54 PM UTC-4, olcott wrote:
    On 5/23/2022 8:05 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 8:57:46 PM UTC-4, olcott wrote:
    On 5/23/2022 7:44 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 7:50:36 PM UTC-4, olcott wrote:
    On 5/23/2022 6:33 PM, Richard Damon wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>>
    On 5/23/22 3:05 PM, olcott wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>>> On 5/23/2022 1:52 PM, Mr Flibble wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>>>> A simple multiple choice question for Olcott: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>
    All things being equal which is more likely: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>
    (a) Olcott is correct and everybody else is incorrect
    (b) Olcott is incorrect and everybody else is correct

    ?

    /Flibble


    Believability has the word [lie] embedded directly within
    itself.
    Instead of the fake measure of credibility one must employ
    actual
    validation.

    Actual validation conclusively proves that H(P,P)==0
    is correct. This means that everyone that disagrees is either
    insufficiently technically competent or a liar. >>>>>>>>>>>>>>>>>>>>>>>>>>>
    You consider that H(P,P) == 0 is correct when P(P) halts,
    when that is
    the DEFINITION of what H(P,P) is supposed to be answering?
    The C function H correctly determines that there are no number
    of steps
    (0 to infinity) of its correct simulation of its input: a pair of
    pointers to finite strings of x86 machine language that would
    ever reach
    the last instruction of this input. >>>>>>>>>>>>>>>>>>>>>>>>>
    But since H has a fixed algorithm, it can't simulate for an
    infinite number of steps. It can only simulate P for some n
    number of steps.

    None-the-less on the basis of matching known behavior patterns H
    can
    determine what the behavior of the input would be if it did
    simulate an
    infinite number of steps.

    So because Pn(Pn) does not halt then Ha(Pa,Pa)==0 is correct?

    No jackass, infinite loop does not halt because infinite loop is an
    infinite loop.
    _Infinite_Loop()
    [000012c2](01) 55 push ebp
    [000012c3](02) 8bec mov ebp,esp
    [000012c5](02) ebfe jmp 000012c5
    [000012c7](01) 5d pop ebp
    [000012c8](01) c3 ret
    Size in bytes:(0007) [000012

    Irrelevant, because this isn't part of any P. >>>>>>>>>>>>>>>>>>>>>
    It not irrelevant jackass it proves that H can detect that an infinite
    simulation would never halt without performing an infinite simulation.

    An infinite loop and the infinite simulation in Pn(Pn) are different,

    It sure is _Infinite_Loop() is on topic and H(P,P) is on topic
    and Pn(Pn) is a strawman error intentionally designed to deceive.


    If _Infinite_Loop, which isn't at all related to P is on topic, then Pn,
    which is one of the P's you talk about must be. >>>>>>>>>>>>>>>>>
    I get to decide what is on topic and what is off topic, I own the topic.
    Remember, you confusingly talk about a CLASS of H's since the H you keep
    on mentioning doesn't have a distinct rule (since if changes how much is
    simulates to be every possible length of simulation), thus giving them
    distinct names is a reasonable thing to do.
    I am referring to one machine language immutable literal string named H
    and another immutable machine language literal string named P. >>>>>>>>>>>>>>>
    Then we'll refer to H as Ha and refer to P as Pa. >>>>>>>>>>>>>> No we will not.

    We all know exactly why not. Because by being clear about which H and which P we're talking about, it exposes the holes in your argument and makes it clear exactly where the problem is. So as Ben has said, clarity is your enemy.

    So explain exactly what is wrong with the below statement. Failure to explain in detail why it is wrong in your next post will be taken as not being able to explain why it is wrong and an acceptance that it is correct. Stating "strawman"
    without an explanation will be taken as a failure to explain.

    Simulating the input to Ha(Pa,Pa) up to an infinite number of steps is done by UTM(Pa,Pa) which halts, so Ha(Pa,Pa)==0 is wrong. And Hb(Pa,Pa)==1 which also shows that Ha(Pa,Pa)==0 is wrong. And yes the input to Ha(Pa,Pa) is the same as the
    input to Hb(Pa,Pa), and you have no basis to claim otherwise.

    It is just like you are saying that because the dog named Spot is black
    and the cat named Fluffy is white therefore the dog named Rover cannot
    be brown.

    Ha(Pa,Pa)
    Hb(Pa,Pa)

    Simulate(Pa,Pa)

    are computationally distinct at the x86 machine language level >>>>>>>>>>>> and you have always known this therefore you are a damned liar. >>>>>>>>>>>
    I know that you *claim* they are distinct, but you have nothing to back that up. Both Ha and Hb are halt deciders and both are given the same exact input.

    P does not call anything besides H

    And because the fixed algorithm of H aborts, then H is the same as Ha and P is therefore the same as Pa.
    How dishonest can you get?
    It is the same as if you claimed that 5 == 6

    Because they have entirely different execution traces

    They're identical up to the point that Ha aborts,
    They are not identical therefore it is either ridiculously stupid to >>>>>> claim that they should have the same behavior or in your case (because >>>>>> we know that you are not stupid) it would be dishonest.

    If Ha(Pa,Pa) and Hb(Pa,Pa) are not identical because as you claim the traces differ, then that would also mean that
    Since you always knew this: that you are a liar when
    you claimed that they are equivalent.
    I know that you *claim* they are distinct, but you have nothing >>>> to back that up.
    I don't think that we are getting anywhere.

    Translation: You can't explain why I'm wrong and you're backed into a corner.


    All of the recent discussions are simply disagreement with an easily
    verifiable fact. Any smart software engineer with a sufficient technical >>>> background can easily confirm that H(P,P)==0 is correct:

    It is an easily verified fact that Ha(Pa,Pa)==0 is NOT correct > as Hb(Pa,Pa)==1 demonstrates that Ha aborted too soon. By the
    definition of the problem any H is required to map the halting function,
    which means the correct answer for Ha(Pa,Pa) and Hb(Pa,Pa) is 1 because
    Pa(Pa) halts. Any claim that Ha(Pa,Pa) and Hb(Pa,Pa) are not deciding
    the same thing is baseless.
    A software engineer with sufficient technical competence would disagree.

    So no explanation why this is wrong, just a baseless claim.

    In other words you are ignoring my explanation and making up the Jackass
    lie that I never explained it.

    On 5/23/2022 9:32 PM, olcott wrote:
    On 5/23/2022 9:23 PM, Dennis Bush wrote:>> So explain exactly what is
    wrong with the below statement. >>
    Simulating the input to Ha(Pa,Pa) up to an infinite number of steps is
    done by UTM(Pa,Pa) which halts, so Ha(Pa,Pa)==0 is wrong. And
    Hb(Pa,Pa)==1 which also shows that Ha(Pa,Pa)==0 is wrong. And yes the
    input to Ha(Pa,Pa) is the same as the input to Hb(Pa,Pa), and you have
    no basis to claim otherwise.


    It is just like you are saying that because the dog named Spot is black
    and the cat named Fluffy is white therefore the dog named Rover cannot
    be brown.

    Ha(Pa,Pa)
    Hb(Pa,Pa)
    Simulate(Pa,Pa)

    are computationally distinct at the x86 machine language level
    and you have always known this therefore you are a damned liar.


    --
    Copyright 2022 Pete Olcott

    "Talent hits a target no one else can hit;
    Genius hits a target no one else can see."
    Arthur Schopenhauer

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)
  • From olcott@21:1/5 to Dennis Bush on Tue May 24 10:59:38 2022
    XPost: comp.theory, sci.logic, sci.math

    On 5/24/2022 10:25 AM, Dennis Bush wrote:
    On Tuesday, May 24, 2022 at 10:57:12 AM UTC-4, olcott wrote:
    On 5/24/2022 9:47 AM, Dennis Bush wrote:
    On Tuesday, May 24, 2022 at 10:19:28 AM UTC-4, olcott wrote:
    On 5/24/2022 8:57 AM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 11:47:56 PM UTC-4, olcott wrote:
    On 5/23/2022 10:16 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 11:08:54 PM UTC-4, olcott wrote:
    On 5/23/2022 10:05 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 11:01:56 PM UTC-4, olcott wrote: >>>>>>>>>> On 5/23/2022 9:57 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 10:48:39 PM UTC-4, olcott wrote: >>>>>>>>>>>> On 5/23/2022 9:40 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 10:32:55 PM UTC-4, olcott wrote: >>>>>>>>>>>>>> On 5/23/2022 9:23 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 10:18:37 PM UTC-4, olcott wrote: >>>>>>>>>>>>>>>> On 5/23/2022 9:09 PM, Dennis Bush wrote:
    On Monday, May 23, 2022 at 9:50:28 PM UTC-4, olcott wrote: >>>>>>>>>>>>>>>>>> On 5/23/2022 8:40 PM, Richard Damon wrote: >>>>>>>>>>>>>>>>>>> On 5/23/22 9:34 PM, olcott wrote:
    On 5/23/2022 8:29 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 9:24:47 PM UTC-4, olcott wrote:
    On 5/23/2022 8:15 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 9:08:54 PM UTC-4, olcott wrote:
    On 5/23/2022 8:05 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 8:57:46 PM UTC-4, olcott wrote:
    On 5/23/2022 7:44 PM, Dennis Bush wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>> On Monday, May 23, 2022 at 7:50:36 PM UTC-4, olcott wrote:
    On 5/23/2022 6:33 PM, Richard Damon wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>
    On 5/23/22 3:05 PM, olcott wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 5/23/2022 1:52 PM, Mr Flibble wrote: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> A simple multiple choice question for Olcott: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
    All things being equal which is more likely: >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
    (a) Olcott is correct and everybody else is incorrect
    (b) Olcott is incorrect and everybody else is correct

    ?

    /Flibble


    Believability has the word [lie] embedded directly within
    itself.
    Instead of the fake measure of credibility one must employ
    actual
    validation.

    Actual validation conclusively proves that H(P,P)==0
    is correct. This means that everyone that disagrees is either
    insufficiently technically competent or a liar. >>>>>>>>>>>>>>>>>>>>>>>>>>>>>
    You consider that H(P,P) == 0 is correct when P(P) halts,
    when that is
    the DEFINITION of what H(P,P) is supposed to be answering?
    The C function H correctly determines that there are no number
    of steps
    (0 to infinity) of its correct simulation of its input: a pair of
    pointers to finite strings of x86 machine language that would
    ever reach
    the last instruction of this input. >>>>>>>>>>>>>>>>>>>>>>>>>>>
    But since H has a fixed algorithm, it can't simulate for an
    infinite number of steps. It can only simulate P for some n
    number of steps.

    None-the-less on the basis of matching known behavior patterns H
    can
    determine what the behavior of the input would be if it did
    simulate an
    infinite number of steps.

    So because Pn(Pn) does not halt then Ha(Pa,Pa)==0 is correct?

    No jackass, infinite loop does not halt because infinite loop is an
    infinite loop.
    _Infinite_Loop()
    [000012c2](01) 55 push ebp
    [000012c3](02) 8bec mov ebp,esp >>>>>>>>>>>>>>>>>>>>>>>> [000012c5](02) ebfe jmp 000012c5 >>>>>>>>>>>>>>>>>>>>>>>> [000012c7](01) 5d pop ebp
    [000012c8](01) c3 ret
    Size in bytes:(0007) [000012

    Irrelevant, because this isn't part of any P. >>>>>>>>>>>>>>>>>>>>>>>
    It not irrelevant jackass it proves that H can detect that an infinite
    simulation would never halt without performing an infinite simulation.

    An infinite loop and the infinite simulation in Pn(Pn) are different,

    It sure is _Infinite_Loop() is on topic and H(P,P) is on topic
    and Pn(Pn) is a strawman error intentionally designed to deceive.


    If _Infinite_Loop, which isn't at all related to P is on topic, then Pn,
    which is one of the P's you talk about must be. >>>>>>>>>>>>>>>>>>>
    I get to decide what is on topic and what is off topic, I own the topic.
    Remember, you confusingly talk about a CLASS of H's since the H you keep
    on mentioning doesn't have a distinct rule (since if changes how much is
    simulates to be every possible length of simulation), thus giving them
    distinct names is a reasonable thing to do. >>>>>>>>>>>>>>>>>> I am referring to one machine language immutable literal string named H
    and another immutable machine language literal string named P.

    Then we'll refer to H as Ha and refer to P as Pa. >>>>>>>>>>>>>>>> No we will not.

    We all know exactly why not. Because by being clear about which H and which P we're talking about, it exposes the holes in your argument and makes it clear exactly where the problem is. So as Ben has said, clarity is your enemy.

    So explain exactly what is wrong with the below statement. Failure to explain in detail why it is wrong in your next post will be taken as not being able to explain why it is wrong and an acceptance that it is correct. Stating "strawman"
    without an explanation will be taken as a failure to explain.

    Simulating the input to Ha(Pa,Pa) up to an infinite number of steps is done by UTM(Pa,Pa) which halts, so Ha(Pa,Pa)==0 is wrong. And Hb(Pa,Pa)==1 which also shows that Ha(Pa,Pa)==0 is wrong. And yes the input to Ha(Pa,Pa) is the same as
    the input to Hb(Pa,Pa), and you have no basis to claim otherwise. >>>>>>>>>>>>>>>
    It is just like you are saying that because the dog named Spot is black
    and the cat named Fluffy is white therefore the dog named Rover cannot
    be brown.

    Ha(Pa,Pa)
    Hb(Pa,Pa)

    Simulate(Pa,Pa)

    are computationally distinct at the x86 machine language level >>>>>>>>>>>>>> and you have always known this therefore you are a damned liar. >>>>>>>>>>>>>
    I know that you *claim* they are distinct, but you have nothing to back that up. Both Ha and Hb are halt deciders and both are given the same exact input.

    P does not call anything besides H

    And because the fixed algorithm of H aborts, then H is the same as Ha and P is therefore the same as Pa.
    How dishonest can you get?
    It is the same as if you claimed that 5 == 6

    Because they have entirely different execution traces

    They're identical up to the point that Ha aborts,
    They are not identical therefore it is either ridiculously stupid to >>>>>>>> claim that they should have the same behavior or in your case (because >>>>>>>> we know that you are not stupid) it would be dishonest.

    If Ha(Pa,Pa) and Hb(Pa,Pa) are not identical because as you claim the traces differ, then that would also mean that
    Since you always knew this: that you are a liar when
    you claimed that they are equivalent.
    I know that you *claim* they are distinct, but you have nothing >>>>>> to back that up.
    I don't think that we are getting anywhere.

    Translation: You can't explain why I'm wrong and you're backed into a corner.


    All of the recent discussions are simply disagreement with an easily >>>>>> verifiable fact. Any smart software engineer with a sufficient technical >>>>>> background can easily confirm that H(P,P)==0 is correct:

    It is an easily verified fact that Ha(Pa,Pa)==0 is NOT correct > as Hb(Pa,Pa)==1 demonstrates that Ha aborted too soon. By the
    definition of the problem any H is required to map the halting function, >>>> which means the correct answer for Ha(Pa,Pa) and Hb(Pa,Pa) is 1 because >>>> Pa(Pa) halts. Any claim that Ha(Pa,Pa) and Hb(Pa,Pa) are not deciding
    the same thing is baseless.
    A software engineer with sufficient technical competence would disagree. >>>
    So no explanation why this is wrong, just a baseless claim.
    In other words you are ignoring my explanation and making up the Jackass
    lie that I never explained it.

    And you seem to forget that I shot that down (see below)


    On 5/23/2022 9:32 PM, olcott wrote:
    On 5/23/2022 9:23 PM, Dennis Bush wrote:>> So explain exactly what is
    wrong with the below statement. >>
    Simulating the input to Ha(Pa,Pa) up to an infinite number of steps is >>>> done by UTM(Pa,Pa) which halts, so Ha(Pa,Pa)==0 is wrong. And
    Hb(Pa,Pa)==1 which also shows that Ha(Pa,Pa)==0 is wrong. And yes the
    input to Ha(Pa,Pa) is the same as the input to Hb(Pa,Pa), and you have >>>> no basis to claim otherwise.


    It is just like you are saying that because the dog named Spot is black
    and the cat named Fluffy is white therefore the dog named Rover cannot
    be brown.

    Ha(Pa,Pa)
    Hb(Pa,Pa)
    Simulate(Pa,Pa)

    are computationally distinct at the x86 machine language level
    and you have always known this therefore you are a damned liar.

    As I stated previously which you dishonestly clipped:

    I know that you *claim* they are distinct, but you have nothing to back that up.
    _P()
    [00001352](01) 55 push ebp
    [00001353](02) 8bec mov ebp,esp
    [00001355](03) 8b4508 mov eax,[ebp+08]
    [00001358](01) 50 push eax // push P
    [00001359](03) 8b4d08 mov ecx,[ebp+08]
    [0000135c](01) 51 push ecx // push P
    [0000135d](05) e840feffff call 000011a2 // call H
    [00001362](03) 83c408 add esp,+08
    [00001365](02) 85c0 test eax,eax
    [00001367](02) 7402 jz 0000136b
    [00001369](02) ebfe jmp 00001369
    [0000136b](01) 5d pop ebp
    [0000136c](01) c3 ret
    Size in bytes:(0027) [0000136c]

    It is self-evident that the simulated input to H1(P,P) has a different execution trace than the simulated input to H(P,P) because H1 does not
    have a pathological self-reference (Olcott 2004) relationship with P.

    void P(u32 x)
    {
    if (H(x, x))
    HERE: goto HERE;
    return;
    }

    int main()
    {
    Output("Input_Halts = ", H1((u32)P, (u32)P));
    }

    _P()
    [00001352](01) 55 push ebp
    [00001353](02) 8bec mov ebp,esp
    [00001355](03) 8b4508 mov eax,[ebp+08]
    [00001358](01) 50 push eax
    [00001359](03) 8b4d08 mov ecx,[ebp+08]
    [0000135c](01) 51 push ecx
    [0000135d](05) e840feffff call 000011a2 // call H
    [00001362](03) 83c408 add esp,+08
    [00001365](02) 85c0 test eax,eax
    [00001367](02) 7402 jz 0000136b
    [00001369](02) ebfe jmp 00001369
    [0000136b](01) 5d pop ebp
    [0000136c](01) c3 ret
    Size in bytes:(0027) [0000136c]

    _main()
    [00001372](01) 55 push ebp
    [00001373](02) 8bec mov ebp,esp
    [00001375](05) 6852130000 push 00001352 // push P
    [0000137a](05) 6852130000 push 00001352 // push P
    [0000137f](05) e81efcffff call 00000fa2 // call H1
    [00001384](03) 83c408 add esp,+08
    [00001387](01) 50 push eax
    [00001388](05) 6823040000 push 00000423
    [0000138d](05) e8e0f0ffff call 00000472
    [00001392](03) 83c408 add esp,+08
    [00001395](02) 33c0 xor eax,eax
    [00001397](01) 5d pop ebp
    [00001398](01) c3 ret
    Size in bytes:(0039) [00001398]



    machine stack stack machine assembly
    address address data code language
    ======== ======== ======== ========= ============= ...[00001372][0010229e][00000000] 55 push ebp ...[00001373][0010229e][00000000] 8bec mov ebp,esp ...[00001375][0010229a][00001352] 6852130000 push 00001352 // push P ...[0000137a][00102296][00001352] 6852130000 push 00001352 // push P ...[0000137f][00102292][00001384] e81efcffff call 00000fa2 // call H1

    Begin Local Halt Decider Simulation Execution Trace Stored at:212352 H1_Root:1
    ...[00001352][0021233e][00212342] 55 push ebp ...[00001353][0021233e][00212342] 8bec mov ebp,esp ...[00001355][0021233e][00212342] 8b4508 mov eax,[ebp+08] ...[00001358][0021233a][00001352] 50 push eax // push P ...[00001359][0021233a][00001352] 8b4d08 mov ecx,[ebp+08] ...[0000135c][00212336][00001352] 51 push ecx // push P ...[0000135d][00212332][00001362] e840feffff call 000011a2 // call H

    Begin Local Halt Decider Simulation Execution Trace Stored at:25cd7a ...[00001352][0025cd66][0025cd6a] 55 push ebp ...[00001353][0025cd66][0025cd6a] 8bec mov ebp,esp ...[00001355][0025cd66][0025cd6a] 8b4508 mov eax,[ebp+08] ...[00001358][0025cd62][00001352] 50 push eax // push P ...[00001359][0025cd62][00001352] 8b4d08 mov ecx,[ebp+08] ...[0000135c][0025cd5e][00001352] 51 push ecx // push P ...[0000135d][0025cd5a][00001362] e840feffff call 000011a2 // call H ...[00001352][002a778e][002a7792] 55 push ebp ...[00001353][002a778e][002a7792] 8bec mov ebp,esp ...[00001355][002a778e][002a7792] 8b4508 mov eax,[ebp+08] ...[00001358][002a778a][00001352] 50 push eax // push P ...[00001359][002a778a][00001352] 8b4d08 mov ecx,[ebp+08] ...[0000135c][002a7786][00001352] 51 push ecx // push P ...[0000135d][002a7782][00001362] e840feffff call 000011a2 // call H
    Local Halt Decider: Infinite Recursion Detected Simulation Stopped ...[00001362][0021233e][00212342] 83c408 add esp,+08 ...[00001365][0021233e][00212342] 85c0 test eax,eax ...[00001367][0021233e][00212342] 7402 jz 0000136b ...[0000136b][00212342][0000107a] 5d pop ebp ...[0000136c][00212346][00001352] c3 ret ...[00001384][0010229e][00000000] 83c408 add esp,+08 ...[00001387][0010229a][00000001] 50 push eax ...[00001388][00102296][00000423] 6823040000 push 00000423 ---[0000138d][00102296][00000423] e8e0f0ffff call 00000472
    Input_Halts = 1
    ...[00001392][0010229e][00000000] 83c408 add esp,+08 ...[00001395][0010229e][00000000] 33c0 xor eax,eax ...[00001397][001022a2][00100000] 5d pop ebp ...[00001398][001022a6][00000004] c3 ret
    Number of Instructions Executed(398230) = 5,944 pages





    --
    Copyright 2022 Pete Olcott

    "Talent hits a target no one else can hit;
    Genius hits a target no one else can see."
    Arthur Schopenhauer

    --- SoupGate-Win32 v1.05
    * Origin: fsxNet Usenet Gateway (21:1/5)